Math Problem Statement

In a school, one fifth of the students have blue eyes. One tenth of the left-handed students have blue eyes. One quarter of the right- handed students have blue eyes. What fraction of the students are left-handed?

Solution

Let's solve the problem step by step by assigning variables and setting up equations.

Step 1: Define the variables

  • Let SS be the total number of students.
  • Let LL be the number of left-handed students.
  • Let RR be the number of right-handed students.

Since every student is either left-handed or right-handed: S=L+RS = L + R

Step 2: Express the number of blue-eyed students

  • One fifth of the total students have blue eyes, so the number of students with blue eyes is: 15S\frac{1}{5}S
  • One tenth of the left-handed students have blue eyes, so the number of left-handed students with blue eyes is: 110L\frac{1}{10}L
  • One quarter of the right-handed students have blue eyes, so the number of right-handed students with blue eyes is: 14R\frac{1}{4}R

Step 3: Set up the equation for the blue-eyed students

The total number of blue-eyed students is the sum of the left-handed and right-handed students with blue eyes: 15S=110L+14R\frac{1}{5}S = \frac{1}{10}L + \frac{1}{4}R

Step 4: Substitute R=SLR = S - L into the equation

Substitute R=SLR = S - L into the equation to express everything in terms of LL and SS: 15S=110L+14(SL)\frac{1}{5}S = \frac{1}{10}L + \frac{1}{4}(S - L)

Step 5: Simplify the equation

First, eliminate the fractions by multiplying the entire equation by 20 (the least common multiple of 5, 10, and 4): 4S=2L+5(SL)4S = 2L + 5(S - L) Simplify the equation: 4S=2L+5S5L4S = 2L + 5S - 5L Combine like terms: 4S5S=3L4S - 5S = -3L S=3L-S = -3L Divide both sides by -1: S=3LS = 3L

Step 6: Solve for the fraction of left-handed students

Since S=3LS = 3L, the fraction of left-handed students is: LS=L3L=13\frac{L}{S} = \frac{L}{3L} = \frac{1}{3}

Final Answer

The fraction of the students who are left-handed is 13\frac{1}{3}.

Would you like more details or have any questions? Here are some additional questions related to this problem:

  1. If the total number of students is 300, how many are left-handed?
  2. What fraction of the right-handed students do not have blue eyes?
  3. If 60 students have blue eyes, how many are left-handed and have blue eyes?
  4. What fraction of the students do not have blue eyes?
  5. How would the result change if one eighth of the right-handed students had blue eyes instead?

Tip: Setting up equations with variables and systematically eliminating them can simplify complex word problems.

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Math Problem Analysis

Mathematical Concepts

Equations
Fractions
Proportions

Formulas

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Theorems

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Suitable Grade Level

Grades 5-6