Assume that you found that the average volume of water required to fill the graduated cylinder to the 8.00 mL mark was 7.95 mL. What is the percent error?

To calculate the percent error, we use the formula:

\[
\text{Percent Error} = \left( \frac{\text{Experimental Value} - \text{Theoretical Value}}{\text{Theoretical Value}} \right) \times 100
\]

In this case:
- The **experimental value** is the volume of water actually measured, which is \( 7.95 \) mL.
- The **theoretical value** is the intended or accepted volume, which is \( 8.00 \) mL.

Now, plug in these values to find the percent error:

\[
\text{Percent Error} = \left( \frac{7.95 - 8.00}{8.00} \right) \times 100
\]

Let's calculate this:

\[
\text{Percent Error} = \left( \frac{-0.05}{8.00} \right) \times 100 = \left( -0.00625 \right) \times 100 = -0.625\%
\]

Since percent error is usually expressed as a positive value, we take the absolute value:

\[
\text{Percent Error} = 0.625\%
\]

### Conclusion:
The percent error in measuring the volume is **0.625%**.

Would you like further details or have any questions? Here are some related questions you might consider:

1. What are some factors that could cause percent error in a volume measurement?
2. How does the precision of the measuring instrument affect the percent error?
3. Can percent error be greater than 100%? Under what circumstances?
4. How would you minimize errors in a laboratory setting?
5. What is the difference between percent error and absolute error?

**Tip:** Percent error helps to understand how accurate a measurement is compared to the accepted value.

Learn how to calculate the percent error when the average measured volume of water is 7.95 mL, and the theoretical value is 8.00 mL. This problem covers percent error calculations, helping students understand measurement accuracy and precision. Suitable for high school students in Grades 9-12.

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