https://file.aiquickdraw.com/mathbot/file/1726249679130agwm9902.jpg

To solve the problem from the image, we need to calculate both the absolute error and the percent error based on the given information:

### Given:
- **Estimated volume** = 30 mL
- **Actual volume** = 28.1 mL

### 1. Absolute Error:
The absolute error is the difference between the estimated value and the actual value.

\[
\text{Absolute Error} = |\text{Estimated Value} - \text{Actual Value}|
\]

\[
\text{Absolute Error} = |30 - 28.1| = 1.9 \, \text{mL}
\]

### 2. Percent Error:
The percent error is calculated using the formula:

\[
\text{Percent Error} = \left( \frac{\text{Absolute Error}}{\text{Actual Value}} \right) \times 100
\]

\[
\text{Percent Error} = \left( \frac{1.9}{28.1} \right) \times 100 \approx 6.8\%
\]

### Final Answers:
- **Absolute Error** = 1.9 mL
- **Percent Error** = 6.8%

Would you like more details on this solution or have any questions?

Here are five related questions for further practice:
1. What is the absolute error if the estimated volume is 50 mL and the actual volume is 48.5 mL?
2. How does increasing the actual volume affect the percent error, assuming the same absolute error?
3. If the estimated volume is 25 mL and the percent error is 4%, what is the actual volume?
4. How would you interpret the percent error in practical terms in a laboratory setting?
5. Why is it important to round the percent error to the nearest tenth in some cases?

**Tip:** Always ensure that you're using the actual value (not the estimated one) in the denominator when calculating percent error.

A chemist estimated the volume of a solution in a test tube to be 30 mL. The actual volume of the solution was 28.1 mL. Find the absolute error and the percent error of the chemist's estimate. Round your answers to the nearest tenth.

Learn how to calculate the absolute error and percent error of a chemist's estimate of a solution volume in a test tube. The estimated volume is 30 mL, and the actual volume is 28.1 mL. Step-by-step guide with relevant formulas, suitable for Grades 7-9.

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