Math Problem Statement

The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s − 2 sin πt 1 3 cos πt, where t is measured in seconds

Solution

It seems like you're describing the displacement of a particle along a straight line, given by the equation:

s(t)=2sin(πt)+3cos(πt)s(t) = 2 \sin(\pi t) + 3 \cos(\pi t) where s(t)s(t) is the displacement in centimeters, and tt is the time in seconds.

Would you like help solving a specific problem related to this equation? For instance, we can calculate the velocity, acceleration, or find the position at a certain time.

Let me know what you'd like to do! Here's a list of possible related questions:

  1. What is the velocity of the particle at time tt?
  2. What is the acceleration of the particle at time tt?
  3. What is the maximum displacement of the particle?
  4. How do we calculate the period of the motion?
  5. What is the phase of the motion at a specific time?

Tip: To analyze motion equations like this one, it's useful to remember that the displacement equation is typically in the form s(t)=Asin(ωt+ϕ)s(t) = A \sin(\omega t + \phi), where AA is the amplitude, ω\omega is the angular frequency, and ϕ\phi is the phase constant.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Differentiation
Kinematics

Formulas

Displacement equation: s(t) = 2 sin(πt) + 3 cos(πt)
Velocity: v(t) = ds/dt
Acceleration: a(t) = d²s/dt²

Theorems

Derivative rules for sine and cosine functions

Suitable Grade Level

Grades 10-12