Find the parametric and symmetric equation of the line through the points (-1,4,-3) and (4,2,-1).

To find the parametric and symmetric equations of the line passing through the points \((-1, 4, -3)\) and \((4, 2, -1)\), follow these steps:

### Step 1: Find the direction vector
The direction vector \(\mathbf{v}\) is the vector from the first point to the second point. It is given by:

\[
\mathbf{v} = (x_2 - x_1, y_2 - y_1, z_2 - z_1)
\]

Substituting the points \((-1, 4, -3)\) and \((4, 2, -1)\):

\[
\mathbf{v} = (4 - (-1), 2 - 4, -1 - (-3)) = (5, -2, 2)
\]

So, the direction vector is \(\mathbf{v} = (5, -2, 2)\).

### Step 2: Parametric equations of the line
The parametric equations of a line are given by:

\[
x = x_1 + t \cdot v_x, \quad y = y_1 + t \cdot v_y, \quad z = z_1 + t \cdot v_z
\]

Here, \((x_1, y_1, z_1)\) is the point \((-1, 4, -3)\), and \((v_x, v_y, v_z)\) are the components of the direction vector \((5, -2, 2)\). Substituting these values:

\[
x = -1 + 5t, \quad y = 4 - 2t, \quad z = -3 + 2t
\]

Thus, the parametric equations of the line are:

\[
\boxed{x = -1 + 5t, \quad y = 4 - 2t, \quad z = -3 + 2t}
\]

### Step 3: Symmetric equation of the line
To find the symmetric equation, solve each parametric equation for \(t\):

1. From \(x = -1 + 5t\), we get \(t = \frac{x + 1}{5}\).
2. From \(y = 4 - 2t\), we get \(t = \frac{4 - y}{2}\).
3. From \(z = -3 + 2t\), we get \(t = \frac{z + 3}{2}\).

Now, equate all these expressions for \(t\):

\[
\frac{x + 1}{5} = \frac{4 - y}{2} = \frac{z + 3}{2}
\]

Thus, the symmetric equation of the line is:

\[
\boxed{\frac{x + 1}{5} = \frac{4 - y}{2} = \frac{z + 3}{2}}
\]

Would you like more details on any step or clarification?

---

Here are 5 questions to expand your knowledge:
1. How can you find the equation of a line in vector form using parametric equations?
2. How would you determine if two lines in space are parallel?
3. Can parametric equations represent curves other than lines?
4. What is the physical interpretation of the direction vector in 3D space?
5. How can you derive the Cartesian equation of a plane from three points?

**Tip:** When solving geometric problems in 3D, the direction vector plays a crucial role in defining lines and angles between them.

Discover how to find the parametric and symmetric equations of a line through the points (-1, 4, -3) and (4, 2, -1). This solution covers key 3D geometry concepts, including direction vectors and line equations. Suitable for high school students in Grades 10-12.

Math Problem Statement

Solution

Ask a new question for Free

By Image

Math Problem Analysis

Mathematical Concepts

Formulas

Theorems

Suitable Grade Level

Related Recommendation