Math Problem Statement

equation of The line passing through (−5, 0, 4) and (6, −3, 2)

Solution

To find the equation of the line passing through two points in 3D space, we need to use the vector form of the line equation. The general equation of a line passing through two points P1(x1,y1,z1)P_1(x_1, y_1, z_1) and P2(x2,y2,z2)P_2(x_2, y_2, z_2) can be written as:

r(t)=r0+td\mathbf{r}(t) = \mathbf{r}_0 + t \mathbf{d}

where:

  • r(t)\mathbf{r}(t) is the position vector of a point on the line,
  • r0\mathbf{r}_0 is the position vector of the first point P1P_1,
  • d\mathbf{d} is the direction vector (calculated by subtracting the coordinates of P2P_2 and P1P_1),
  • tt is a scalar parameter.

Step 1: Find the direction vector

The direction vector d\mathbf{d} is given by:

d=P2P1=(x2x1,y2y1,z2z1)\mathbf{d} = P_2 - P_1 = (x_2 - x_1, y_2 - y_1, z_2 - z_1)

Substitute the coordinates of the points P1(5,0,4)P_1(-5, 0, 4) and P2(6,3,2)P_2(6, -3, 2):

d=(6(5),30,24)=(11,3,2)\mathbf{d} = (6 - (-5), -3 - 0, 2 - 4) = (11, -3, -2)

Step 2: Write the parametric equation of the line

Using the direction vector d=(11,3,2)\mathbf{d} = (11, -3, -2) and the point P1(5,0,4)P_1(-5, 0, 4), the parametric equations of the line are:

x=5+11tx = -5 + 11t y=03ty = 0 - 3t z=42tz = 4 - 2t

Final answer:

The parametric equations of the line passing through the points (5,0,4)(-5, 0, 4) and (6,3,2)(6, -3, 2) are:

x=5+11t,y=3t,z=42t\boxed{x = -5 + 11t, \, y = -3t, \, z = 4 - 2t}

Would you like more details or have any questions?


Here are 5 related questions:

  1. How do you find the equation of a plane given three points?
  2. What is the parametric form of a line in 2D space?
  3. How do you convert a parametric equation into a vector equation?
  4. How do you determine if two lines in 3D space are parallel?
  5. What is the distance between two points in 3D space?

Tip: The direction vector gives important information about the orientation of the line, such as its slope and direction.

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Math Problem Analysis

Mathematical Concepts

3D Geometry
Vectors
Parametric Equations

Formulas

Vector form of the line equation: r(t) = r_0 + t * d
Direction vector: d = (x2 - x1, y2 - y1, z2 - z1)
Parametric equations: x = x1 + d_xt, y = y1 + d_yt, z = z1 + d_zt

Theorems

Vector equation of a line in 3D space

Suitable Grade Level

Grades 11-12