Math Problem Statement

Find the matrix corresponding the orthogonal projection in R2 onto the subspace spanned by the vector

Solution

To find the matrix corresponding to the orthogonal projection onto the subspace spanned by a vector v in R2\mathbb{R}^2, we proceed as follows:

Given a vector v=(v1v2)\mathbf{v} = \begin{pmatrix} v_1 \\ v_2 \end{pmatrix}, the projection of any vector u=(u1u2)\mathbf{u} = \begin{pmatrix} u_1 \\ u_2 \end{pmatrix} onto v\mathbf{v} is given by:

projv(u)=uvvvv\text{proj}_{\mathbf{v}}(\mathbf{u}) = \frac{\mathbf{u} \cdot \mathbf{v}}{\mathbf{v} \cdot \mathbf{v}} \mathbf{v}

Step-by-Step:

  1. Find the dot product vv\mathbf{v} \cdot \mathbf{v}: vv=v12+v22\mathbf{v} \cdot \mathbf{v} = v_1^2 + v_2^2

  2. Form the projection formula: projv(u)=u1v1+u2v2v12+v22(v1v2)\text{proj}_{\mathbf{v}}(\mathbf{u}) = \frac{u_1 v_1 + u_2 v_2}{v_1^2 + v_2^2} \begin{pmatrix} v_1 \\ v_2 \end{pmatrix}

  3. Matrix representation: The matrix PP that represents the projection is the matrix such that Pu=projv(u)P\mathbf{u} = \text{proj}_{\mathbf{v}}(\mathbf{u}).

    For a projection onto v=(v1v2)\mathbf{v} = \begin{pmatrix} v_1 \\ v_2 \end{pmatrix}, the matrix PP is given by:

    P=1v12+v22(v12v1v2v1v2v22)P = \frac{1}{v_1^2 + v_2^2} \begin{pmatrix} v_1^2 & v_1 v_2 \\ v_1 v_2 & v_2^2 \end{pmatrix}

Final Matrix Formula:

P=1v12+v22(v12v1v2v1v2v22)P = \frac{1}{v_1^2 + v_2^2} \begin{pmatrix} v_1^2 & v_1 v_2 \\ v_1 v_2 & v_2^2 \end{pmatrix}

This matrix PP projects any vector in R2\mathbb{R}^2 onto the subspace spanned by the vector v=(v1v2)\mathbf{v} = \begin{pmatrix} v_1 \\ v_2 \end{pmatrix}.


Would you like to go over an example or clarify any part of this process? Here are five questions to consider:

  1. How do you verify that the matrix PP is a projection matrix?
  2. How do you check that PP is an orthogonal projection matrix?
  3. What is the difference between orthogonal and oblique projections?
  4. How does the projection matrix behave for special cases like v=(10)\mathbf{v} = \begin{pmatrix} 1 \\ 0 \end{pmatrix}?
  5. Can this method be generalized to projections in Rn\mathbb{R}^n?

Tip: The matrix of an orthogonal projection is always symmetric and idempotent (i.e., P2=PP^2 = P).

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Orthogonal Projections
Matrix Theory

Formulas

proj_v(u) = (u · v / v · v) * v
P = (1 / (v1^2 + v2^2)) * [[v1^2, v1*v2], [v1*v2, v2^2]]

Theorems

Orthogonal Projection Theorem

Suitable Grade Level

Undergraduate Level (College)