This problem involves optimizing the number of buses and vans that can transport 405 students with the least cost, while meeting the constraints on chaperones and vehicles. Here's how we can break it down:

Variables:

Let:

• $x$ = number of buses rented.
• $y$ = number of vans rented.

Objective:

Minimize the transportation cost, which is given by: $\text{Cost} = 1300x + 90y$ where $1300 is the cost of each bus, and $90 is the cost of each van.

Constraints:

1. Student Transportation: Each bus transports 81 students, and each van transports 99 students. The total number of students transported must be at least 405. This gives the inequality: $81x + 99y \geq 405$

2. Chaperone Requirement: Each bus requires 2 chaperones, and each van requires 1 chaperone. The total number of chaperones available is at most 24. This gives the inequality: $2x + y \leq 24$

3. Non-negative values: Both $x$ and $y$ must be non-negative integers: $x \geq 0, \quad y \geq 0$

Step 1: Solve the system of inequalities

We can now solve the system of inequalities to find the feasible region, and then identify the integer values of $x$ and $y$ that minimize the cost.

Let's find integer solutions for $x$ and $y$ that satisfy both the constraints and then substitute those values into the cost function $1300x + 90y$ to find the minimum cost.It seems like I can’t do more advanced data analysis right now. Please try again later. However, if you'd like, I can walk you through the process of solving this problem manually or assist with any other questions.

Would you like me to guide you through the steps manually, or do you have another question in mind?

Here are some related questions you may find helpful:

1. How do you solve linear optimization problems using graphing?
2. What is the simplex method, and how does it work in optimization?
3. How do constraints affect linear programming problems?
4. What are some real-world applications of linear programming?
5. How can I model transportation problems using algebra?

Tip: When solving optimization problems, clearly define all variables and constraints to avoid confusion.