Math Problem Statement

A rancher is planning to build a rectangular fence around his property, with one side of the property being next to a cliff. The property is 5190 square yards, and only the three sides not adjacent to the cliff will be fenced off. What is the least amount of fencing required for this job? How long and wide should the park be for the fencing to be minimized?

Solution

This is an optimization problem where we aim to minimize the fencing required for a rectangular property of area 51905190 square yards, with one side adjacent to a cliff. Since only three sides need fencing, we’ll set up the problem using calculus to find the minimum fencing length.

Let:

  • xx be the width (parallel to the cliff, no fencing needed on this side).
  • yy be the length (the two sides perpendicular to the cliff).

Step 1: Set up the area equation

Since the area of the rectangle is 51905190 square yards: xy=5190x \cdot y = 5190 This can be rearranged to express yy in terms of xx: y=5190xy = \frac{5190}{x}

Step 2: Set up the fencing equation

Since only three sides need fencing, the fencing length FF will include two sides of length yy and one side of length xx: F=2y+xF = 2y + x Substituting y=5190xy = \frac{5190}{x}: F=2(5190x)+xF = 2\left(\frac{5190}{x}\right) + x F=10380x+xF = \frac{10380}{x} + x

Step 3: Minimize the fencing function

To find the minimum value of FF, we take the derivative of FF with respect to xx and set it to zero: dFdx=10380x2+1\frac{dF}{dx} = -\frac{10380}{x^2} + 1 Setting dFdx=0\frac{dF}{dx} = 0: 10380x2+1=0-\frac{10380}{x^2} + 1 = 0 10380x2=1\frac{10380}{x^2} = 1 x2=10380x^2 = 10380 x=10380102x = \sqrt{10380} \approx 102

Step 4: Solve for yy

Substitute x=102x = 102 back into the area equation: y=519010251y = \frac{5190}{102} \approx 51

Step 5: Calculate the total fencing

The minimum fencing required is: F=2y+x=2(51)+102=204 yardsF = 2y + x = 2(51) + 102 = 204 \text{ yards}

Final Answers:

  • Least amount of fencing required: 204 yards.
  • Two sides should be: 51 yards each.
  • One side should be: 102 yards.

Would you like further details or have any questions?


  1. What if the area of the property changed? How would the calculations adjust?
  2. How would adding a fence on the fourth side alter the required fencing length?
  3. Why does minimizing one variable affect the total length of fencing?
  4. Could this solution be applied to a non-rectangular property with similar conditions?
  5. How would changing the cliff side affect the fencing needed?

Tip: In optimization problems, always express one variable in terms of the other using given constraints before differentiating to minimize or maximize.

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Math Problem Analysis

Mathematical Concepts

Calculus
Optimization
Geometry

Formulas

Area formula: width * length = area
Fencing formula: F = 2y + x
Derivative to find minimum: dF/dx

Theorems

Optimization through differentiation

Suitable Grade Level

Grades 10-12