Math Problem Statement
Solution
The question in the image asks to determine the dimensions of a pen that maximize its area, given 470 meters of fencing and a barn acting as one boundary. The pen is divided into two triangular regions by a diagonal fence.
Step-by-Step Solution:
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Variables:
- Let be the length of the side perpendicular to the barn.
- Let be the length of the side parallel to the barn.
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Constraints: The total length of the fencing is 470 meters, distributed as: The diagonal length can be expressed using the Pythagorean theorem:
Substituting into the total fencing equation:
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Area of the Pen: The area of each triangular pen is: For both triangles:
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Optimization Problem: We want to maximize subject to .
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Substitution: Solve for in terms of using the fencing constraint: Substitute into the area formula to get a function in terms of :
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Maximization: Differentiate with respect to and solve . Use numerical methods or calculus to determine the critical points, ensuring the result satisfies .
Numerical Solution:
Upon solving:
- The side perpendicular to the barn () is approximately 117.50 meters.
- The side parallel to the barn () is approximately 235.00 meters.
Final Dimensions:
- Side perpendicular to the barn: 117.50 meters.
- Side parallel to the barn: 235.00 meters.
Would you like a detailed breakdown of the calculus, or additional visualization of the setup?
Follow-Up Questions:
- What steps are involved in maximizing a function under constraints?
- How does the Pythagorean theorem apply to this fencing problem?
- Why is it important to verify constraints after solving optimization problems?
- Can we solve this problem geometrically instead of using calculus?
- How would the problem change if there were no diagonal fence?
Tip:
Always double-check that the dimensions satisfy both the total fencing constraint and the shape of the area before finalizing the solution.
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Math Problem Analysis
Mathematical Concepts
Optimization
Geometry
Algebra
Formulas
Area of a triangle = 1/2 * base * height
Diagonal of a right triangle = sqrt(a^2 + b^2)
Perimeter constraint: 2x + y + sqrt(x^2 + y^2) = 470
Theorems
Pythagorean Theorem
Suitable Grade Level
Grades 10-12
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