Math Problem Statement

A farmer wants to fence an area of 13.5 million square feet in a rectangular field and then divide it in half with a fence parallel to one of the sides of the rectangle. Let y represent the length (in feet) of a side perpendicular to the dividing fence, and let x represent the length (in feet) of a side parallel to the dividing fence. Let F represent the length of fencing in feet. Write an equation that represents F in terms of the variable x. F(x) =

Incorrect: Your answer is incorrect. Find the derivative F ′(x). F ′(x) =

Incorrect: Your answer is incorrect. Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) x =

Incorrect: Your answer is incorrect.

Solution

Let's break this problem down step-by-step:

Step 1: Set Up the Area Constraint

The area AA of the rectangular field is given by: A=xy=13,500,000square feetA = x \cdot y = 13,500,000 \, \text{square feet} where:

  • xx is the length parallel to the dividing fence,
  • yy is the length perpendicular to the dividing fence.

Since we know the area, we can express yy in terms of xx: y=13,500,000xy = \frac{13,500,000}{x}

Step 2: Express the Fencing Requirement

The total fencing FF consists of:

  1. Two lengths of yy (for the sides perpendicular to the dividing fence),
  2. Three lengths of xx (two outer lengths plus the dividing fence in the middle).

Thus, the equation for FF is: F(x)=2y+3xF(x) = 2y + 3x Substitute y=13,500,000xy = \frac{13,500,000}{x} into this equation: F(x)=2(13,500,000x)+3xF(x) = 2 \left( \frac{13,500,000}{x} \right) + 3x Simplify: F(x)=27,000,000x+3xF(x) = \frac{27,000,000}{x} + 3x

Step 3: Find the Derivative F(x)F'(x)

To find the derivative F(x)F'(x), use the power rule: F(x)=27,000,000x+3x=27,000,000x1+3xF(x) = \frac{27,000,000}{x} + 3x = 27,000,000 \cdot x^{-1} + 3x Differentiating with respect to xx: F(x)=27,000,000x2+3F'(x) = -\frac{27,000,000}{x^2} + 3

Step 4: Find the Critical Numbers

To find the critical points, set F(x)=0F'(x) = 0: 27,000,000x2+3=0-\frac{27,000,000}{x^2} + 3 = 0 Solving for xx: 27,000,000x2=3\frac{27,000,000}{x^2} = 3 x2=27,000,0003=9,000,000x^2 = \frac{27,000,000}{3} = 9,000,000 x=9,000,000=3000x = \sqrt{9,000,000} = 3000

So, the critical number is: x=3000x = 3000

Summary of Answers

  1. The equation for F(x)F(x) in terms of xx is: F(x)=27,000,000x+3xF(x) = \frac{27,000,000}{x} + 3x
  2. The derivative F(x)F'(x) is: F(x)=27,000,000x2+3F'(x) = -\frac{27,000,000}{x^2} + 3
  3. The critical number is: x=3000x = 3000

Would you like more details on any step?

Here are some follow-up questions for further exploration:

  1. What does the critical number x=3000x = 3000 represent in terms of the fencing optimization?
  2. How would the function F(x)F(x) change if the area requirement increased or decreased?
  3. Can we confirm that the critical point minimizes or maximizes the fencing length?
  4. How would the solution change if the dividing fence ran perpendicular to xx instead?
  5. What are the implications for practical fencing in terms of materials and cost based on F(x)F(x)?

Tip: Always double-check each step when setting up an equation to ensure no details are missed!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Optimization
Calculus
Derivatives

Formulas

Area of rectangle: A = x * y
Fencing equation: F(x) = 2y + 3x
Derivative of F(x): F'(x) = -27000000/x^2 + 3

Theorems

Power rule for derivatives

Suitable Grade Level

Grade 11-12