Math Problem Statement
A department store chain has up to $22,000 to spend on television advertising for a sale. All ads will be placed with one television station, where a 30-second ad costs $1,000 on daytime TV and is viewed by 14,000 potential customers, $2,000 on prime-time TV and is viewed by 24,000 potential customers, and $1,500 on late-night TV and is viewed by 18, 000 potential customers. The television station will not accept a total of more than 20 ads in all three time periods. How many ads should be placed in each time period in order to maximize the number of potential customers who will see the ads?
Solution
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Linear Programming
Optimization
Inequalities
Formulas
Objective function: Maximize 14,000x1 + 24,000x2 + 18,000x3
Budget constraint: 1000x1 + 2000x2 + 1500x3 ≤ 22,000
Total ads constraint: x1 + x2 + x3 ≤ 20
Non-negativity constraint: x1 ≥ 0, x2 ≥ 0, x3 ≥ 0
Theorems
Linear Programming Simplex Method
Suitable Grade Level
College Level or Advanced High School
Related Recommendation
Maximizing Audience Reach Using Linear Programming with Budget Constraints
Optimizing Ad Placement Across TV, Social Media, and Print with Budget Constraints
Maximizing Store Exposure with a $9000 Advertising Budget Using Linear Programming
Maximizing Audience Reach with Budget Constraints for Westchester Chamber of Commerce
Linear Programming Problems: Minimizing Bus Miles & Maximizing Ad Audience Reach