Math Problem Statement

ChemLabs uses raw materials / and // to produce two domestic cleaning solutions, A and B. The daily availabilities of raw materials / and // are 150 and 145 units, respectively. One unit of solution A consumes .5 unit of raw material / and .6 unit of raw material II, and one unit of solution B uses .5 unit of raw material / and .4 unit of raw material //. The profits per unit of solutions A and B are $8 and $10, respectively. The daily demand for solution A lies between 30 and 150 units, and that for solution B between 40 and 200 units. Find the optimal production amounts of A and B.

Solution

To solve this optimization problem, we need to maximize the profit while considering the constraints on raw materials and demand. This is a linear programming (LP) problem, where:

  • Objective: Maximize profit by choosing optimal amounts of solutions AA and BB to produce.
  • Constraints: Availability of raw materials, demand for solutions AA and BB, and non-negativity of production amounts.

Step 1: Define the decision variables

Let:

  • x1x_1 = number of units of solution AA produced.
  • x2x_2 = number of units of solution BB produced.

Step 2: Write the objective function

The total profit PP is given by: P=8x1+10x2P = 8x_1 + 10x_2 This is what we want to maximize.

Step 3: Define the constraints

Raw material availability constraints:

  • For raw material //: 0.5x1+0.5x21500.5x_1 + 0.5x_2 \leq 150
  • For raw material ////: 0.6x1+0.4x21450.6x_1 + 0.4x_2 \leq 145

Demand constraints:

  • The demand for solution AA lies between 30 and 150 units: 30x115030 \leq x_1 \leq 150
  • The demand for solution BB lies between 40 and 200 units: 40x220040 \leq x_2 \leq 200

Non-negativity constraints:

x10,x20x_1 \geq 0, \quad x_2 \geq 0

Step 4: Linear programming formulation

The problem can now be formulated as follows:

Maximize: P=8x1+10x2P = 8x_1 + 10x_2

Subject to:

  1. 0.5x1+0.5x21500.5x_1 + 0.5x_2 \leq 150 (raw material / constraint)
  2. 0.6x1+0.4x21450.6x_1 + 0.4x_2 \leq 145 (raw material // constraint)
  3. 30x115030 \leq x_1 \leq 150 (demand for A)
  4. 40x220040 \leq x_2 \leq 200 (demand for B)
  5. x10x_1 \geq 0, x20x_2 \geq 0 (non-negativity constraints)

Step 5: Solve using linear programming

To find the optimal solution, we can use a method such as the Simplex Method or a solver for linear programming. I will now calculate the optimal solution for this problem.The optimal production amounts for ChemLabs are:

  • Produce 100 units of solution AA.
  • Produce 200 units of solution BB.

This results in a maximum profit of $2800 per day.

Would you like further details or have any other questions? Here are some related questions to explore further:

  1. How would the solution change if the availability of raw material //// increased to 160 units?
  2. What happens to the profit if the profit per unit of solution BB decreases to $9?
  3. Can you explain the Simplex Method used in linear programming?
  4. What if the demand for solution BB decreases to a range of 30-100 units?
  5. How would the solution be affected if both raw materials were more expensive?

Tip: Linear programming is useful for optimizing problems with constraints; graphical methods work for two variables, but solvers like Simplex handle larger cases efficiently.

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Math Problem Analysis

Mathematical Concepts

Linear Programming
Optimization
Constraints

Formulas

Profit = 8x1 + 10x2
0.5x1 + 0.5x2 ≤ 150 (raw material / constraint)
0.6x1 + 0.4x2 ≤ 145 (raw material // constraint)
30 ≤ x1 ≤ 150 (demand for solution A)
40 ≤ x2 ≤ 200 (demand for solution B)

Theorems

Simplex Method
Linear Optimization Theorems

Suitable Grade Level

Undergraduate Level or Advanced High School