This is an op-amp circuit problem. Let's analyze the circuit based on the given components.

Given Information:

• $V_s = 8 \, \text{V}$
• There's a 1V DC source at the non-inverting input (+) of the op-amp.
• The feedback resistor is 2 kΩ connected between the output and the inverting input (-).
• We are asked to find the output voltage $V_o$.

Assumptions:

• Since there is a direct connection from the output to the inverting input through the resistor, this is a negative feedback configuration.
• In an ideal op-amp with negative feedback, the voltage at the inverting input (-) is forced to equal the voltage at the non-inverting input (+). So, $V_{-} = V_{+} = 1 \, \text{V}$.

Steps to Solve:

1. Non-inverting input voltage: The voltage at the non-inverting input is given as 1 V.

2. Inverting input voltage: Since this is a negative feedback op-amp, the inverting input voltage will also be 1 V.

3. Voltage across the 2 kΩ resistor: The voltage across the resistor is the difference between the output voltage $V_o$ and the voltage at the inverting input (1 V). Therefore: $V_o - 1 \, \text{V} = I \cdot 2 \, \text{k}\Omega$ where $I$ is the current through the resistor.

4. Current through the 2 kΩ resistor: The current $I$ can be calculated from the source $V_s = 8 \, \text{V}$ and the voltage at the inverting input (1 V): $I = \frac{V_s - 1 \, \text{V}}{R} = \frac{8 \, \text{V} - 1 \, \text{V}}{2 \, \text{k}\Omega} = \frac{7}{2000} \, \text{A} = 3.5 \, \text{mA}$

5. Output voltage: Now, applying Ohm’s Law across the resistor, the voltage difference between the output and inverting input must be: $V_o - 1 = (3.5 \, \text{mA}) \times (2 \, \text{k}\Omega) = 7 \, \text{V}$ So, $V_o = 7 \, \text{V} + 1 \, \text{V} = 8 \, \text{V}$

Final Answer:

The output voltage $V_o$ is 8 V.

Do you have any questions or would you like more details? Here are 5 related questions that could extend your understanding:

1. What is the role of negative feedback in an op-amp?
2. How would the output change if the feedback resistor value increased?
3. What would happen if the non-inverting input voltage changed to 2 V?
4. How would you calculate the output if the resistor was replaced with a 1 kΩ resistor?
5. What is the difference between inverting and non-inverting op-amp configurations?

Tip: Always check the feedback loop in an op-amp circuit, as it dictates the behavior of the amplifier!