The circuit shown in your image is an op-amp circuit with resistors and a current source. We are tasked with calculating the output voltage $v_0$ at the output of the operational amplifier.

Analyzing the circuit:

1. Current Source: A 5 mA current source is connected in parallel with a 5 kΩ resistor. This branch is connected to the negative input of the op-amp through a 20 kΩ resistor.

2. Op-Amp Configuration: The operational amplifier is in a negative feedback configuration, as there is a resistor of 10 kΩ connected between the output and the inverting input. The non-inverting input is grounded, which makes this a non-inverting amplifier.

Steps to solve:

• Since the non-inverting terminal of the op-amp is connected to ground (0V), the voltage at the inverting terminal, $v_1$, will also be approximately 0V (virtual short circuit in ideal op-amp conditions).

• Applying Kirchhoff's Current Law (KCL) at the inverting terminal: $\frac{v_1 - v_0}{10\,k\Omega} + \frac{v_1 - v_{in}}{20\,k\Omega} = 0$ where $v_{in}$ is the voltage across the 5 kΩ resistor due to the 5 mA current source.

Let me calculate these values for you.The output voltage $v_0$ of the circuit is $-12.5 \, \text{V}$.

Would you like more details on the steps or have any other questions?

Here are some related questions for further exploration:

1. How does the virtual short principle in op-amps work?
2. What happens if the feedback resistor values are changed?
3. Can you explain Kirchhoff's Current Law (KCL) in more detail?
4. How would the circuit behave with a non-ideal op-amp?
5. What is the significance of the negative sign in the output voltage?

Tip: In op-amp circuits, the output voltage is often influenced by the ratio of feedback resistors.