Math Problem Statement

The nth term of the sequence shown is defined for each integer n from 1 to 150 as follows: If n is odd, then a_n = (n+1)/2, and if n is even, a_n = n/2. How many integers appear in the sequence twice?

Solution

The problem provided in the image appears to involve a sequence ana_n defined as follows:

  • For odd nn: an=n+12a_n = \frac{n+1}{2}
  • For even nn: an=n2a_n = \frac{n}{2}

The question asks: "How many integers appear in the sequence twice?"

Let's break down the pattern:

  1. Odd nn:

    • For odd nn, the formula is an=n+12a_n = \frac{n+1}{2}. For example:
      • a1=1+12=1a_1 = \frac{1+1}{2} = 1
      • a3=3+12=2a_3 = \frac{3+1}{2} = 2
      • a5=5+12=3a_5 = \frac{5+1}{2} = 3, and so on.
  2. Even nn:

    • For even nn, the formula is an=n2a_n = \frac{n}{2}. For example:
      • a2=22=1a_2 = \frac{2}{2} = 1
      • a4=42=2a_4 = \frac{4}{2} = 2
      • a6=62=3a_6 = \frac{6}{2} = 3, and so on.

Observing Repeated Values:

  • From the formulas, you can observe that:

    • For odd nn, an=n+12a_n = \frac{n+1}{2}
    • For even nn, an=n2a_n = \frac{n}{2}

    These two rules will often result in the same value for two different nn values (one even, one odd). For example:

    • a1=1a_1 = 1 and a2=1a_2 = 1 (both yield 1)
    • a3=2a_3 = 2 and a4=2a_4 = 2 (both yield 2)
    • a5=3a_5 = 3 and a6=3a_6 = 3, and so on.

To find how many numbers appear twice:

  • The numbers that appear twice are exactly those numbers for which both an odd and even nn give the same value.
  • This happens for every pair of consecutive integers. The sequence runs from a1a_1 to a150a_{150}. The odd numbers and even numbers will match in this paired way up to a150a_{150}, leading to repeated values.

Conclusion:

  • The integers from 1 to 75 appear twice because the sequence alternates between odd and even values that pair up in this way.

Thus, 75 integers appear twice.

Given the answer choices (11, 10, 9, 8), it seems like there's a mismatch or misprint in the provided answer options, but logically, 75 integers should appear twice in this sequence.

Would you like more details or have any further questions? Here are some related questions:

  1. How would you determine the largest integer in a similar sequence defined differently?
  2. What is the general pattern for sequences involving odd/even differences?
  3. How can you model sequences with different recurrence relations?
  4. How would the sequence change if the formulas for odd/even terms were switched?
  5. How would you approach finding the sum of the first nn terms in this sequence?

Tip: Sequences like this often alternate between formulas depending on parity (odd/even) of nn. Identifying patterns early can help solve them more efficiently.

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Math Problem Analysis

Mathematical Concepts

Sequences
Arithmetic Patterns
Odd and Even Numbers

Formulas

a_n = (n+1)/2 for odd n
a_n = n/2 for even n

Theorems

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Suitable Grade Level

Grades 10-12