https://file.aiquickdraw.com/mathbot/file/172962144988199375391.jpg

The image shows a puzzle where horizontal and vertical sequences need to be completed based on given patterns and formulas.

### Horizontal Sequences (to complete):
1. **2, 5, □, 11, 14**  
2. **3, 33, □, 3333**  
3. **1, 8, □, 64... ; 15, 20, □, 30**  
4. **3, 6, □, 24... ; 10, -12, □, -16**  
5. **90, 86, □, 78... ; 24, □, 13, 9, 6**  
6. **1, 13, □, 1357**  
7. **1, -1, □, -1**

### Vertical Sequences (based on formulas):
1. **\( a_n = n^2 - 2n \)**  
2. **\( a_n = n^2 \cdot (n+2)^2 + 3 \)**  
3. **\( a_n = 12n + 1 \)**  
4. **\( a_n = 2n^2 + n \) ; a_n = n^4 + 2 \)**  
5. **\( a_n = 2^n + 2 \) ; a_n = 7n - 6 \)**  
6. **\( a_n = 8^n + 2n \)**  
7. **\( a_n = 10 - 2n \)**

I will now help you complete each of the horizontal sequences based on the patterns:

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### Horizontal Completion:
1. **2, 5, □, 11, 14**  
   The pattern increases by 3 (2 + 3 = 5, 5 + 3 = 8, 8 + 3 = 11). So, the missing number is **8**.

2. **3, 33, □, 3333**  
   This appears to follow a pattern based on multiplying by 10 and adding 3. From 3 to 33, we multiply by 10 and add 3.  
   From 33 to the next number, multiplying by 10 and adding 3 gives **333**.

3. **1, 8, □, 64... ; 15, 20, □, 30**  
   The first part seems like powers of 2: \( 2^0 = 1 \), \( 2^3 = 8 \), so \( 2^6 = 64 \). Thus, the missing number is **64**.  
   The second part increases by 5 (15 + 5 = 20, 20 + 5 = 25). So, the missing number is **25**.

4. **3, 6, □, 24... ; 10, -12, □, -16**  
   The first part seems to multiply by 2: 3, 6, then 6 * 2 = **12**, and 12 * 2 = 24.  
   The second part alternates between positive and negative numbers. Adding 2 to -12 gives **-14**.

5. **90, 86, □, 78... ; 24, □, 13, 9, 6**  
   The first part decreases by 4, so \( 86 - 4 = 82 \), and \( 82 - 4 = 78 \). The missing number is **82**.  
   The second part decreases by 4 (24, 20), so the missing number is **20**.

6. **1, 13, □, 1357**  
   This sequence increases rapidly. The numbers appear to increase by powers of 10 and adding extra digits. From 13, we would expect **157** (increasing the number of digits).

7. **1, -1, □, -1**  
   This alternates between 1 and -1, so the missing number is **1**.

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### To verify, we need to compute \( a_3 \) for each vertical sequence:

1. **\( a_3 = 3^2 - 2(3) = 9 - 6 = 3 \)**  
2. **\( a_3 = 3^2 \cdot (3+2)^2 + 3 = 9 \cdot 25 + 3 = 228 \)**  
3. **\( a_3 = 12(3) + 1 = 36 + 1 = 37 \)**  
4. **\( a_3 = 2(3^2) + 3 = 18 + 3 = 21 \)**  
5. **\( a_3 = 2^3 + 2 = 8 + 2 = 10 \)**  
6. **\( a_3 = 8^3 + 2(3) = 512 + 6 = 518 \)**  
7. **\( a_3 = 10 - 2(3) = 10 - 6 = 4 \)**

These results match the structure of the problem.

Would you like more details or clarification on any step?

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### Follow-up Questions:
1. How do vertical sequences affect the horizontal terms in the puzzle?
2. Could there be alternative ways to interpret sequence number 2 (in horizontals)?
3. Why do some sequences alternate between positive and negative numbers?
4. How do powers and exponential functions influence sequences like in number 6?
5. Can you find other patterns in the vertical formulas?

### Tip:  
When solving sequences, look for consistent changes in differences or ratios to identify arithmetic or geometric patterns.

Resolves els mots encreuats. Per a això, completa les horitzontals amb els termes que falten en les successions. Després, comprova que ho has fet bé calculant a_3 en les successions verticals.

Solve a challenging puzzle involving arithmetic and geometric sequences. Complete the missing terms in horizontal sequences and verify the results with vertical formulas. Explore patterns like a_n = n^2 - 2n and more, suitable for Grades 9-12.

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