Math Problem Statement

please use simpsons rule, trapezoid rule, and middle rule to approximate the integral from 0 to 2. THe integral is (^4√ (1+x^2)dx) with n = 8 and please give answers of 6 decimals places. The 4 isn't a muliplcation its the cubed root

Solution

To approximate the integral of 1+x24dx\sqrt[4]{1 + x^2} \, dx from 0 to 2 using Simpson's Rule, Trapezoidal Rule, and Midpoint Rule, we need to calculate the approximate values of the integral with n=8n = 8 subintervals.

The steps for each method are outlined below:

Step 1: General Setup

We are given: f(x)=1+x24f(x) = \sqrt[4]{1 + x^2} and we need to approximate the integral: 021+x24dx\int_0^2 \sqrt[4]{1 + x^2} \, dx with n=8n = 8 subintervals.

The interval is from a=0a = 0 to b=2b = 2, and we divide it into n=8n = 8 subintervals. The width of each subinterval hh is: h=ban=208=0.25h = \frac{b - a}{n} = \frac{2 - 0}{8} = 0.25

Step 2: Trapezoidal Rule

The Trapezoidal Rule formula is: Tn=h2[f(x0)+2i=1n1f(xi)+f(xn)]T_n = \frac{h}{2} \left[ f(x_0) + 2 \sum_{i=1}^{n-1} f(x_i) + f(x_n) \right] where xi=a+ihx_i = a + ih for i=0,1,2,,ni = 0, 1, 2, \dots, n.

Step 3: Midpoint Rule

The Midpoint Rule formula is: Mn=hi=1nf(xi1+xi2)M_n = h \sum_{i=1}^{n} f\left( \frac{x_{i-1} + x_i}{2} \right) where xix_i are the endpoints of the subintervals.

Step 4: Simpson's Rule

Simpson's Rule formula is: Sn=h3[f(x0)+4i=1,3,5,n1f(xi)+2i=2,4,6,n2f(xi)+f(xn)]S_n = \frac{h}{3} \left[ f(x_0) + 4 \sum_{i=1,3,5,\dots}^{n-1} f(x_i) + 2 \sum_{i=2,4,6,\dots}^{n-2} f(x_i) + f(x_n) \right]

I will now calculate the approximations using these methods.Here are the approximations for the integral 021+x24dx\int_0^2 \sqrt[4]{1 + x^2} \, dx using n=8n = 8 subintervals, with results rounded to 6 decimal places:

  1. Trapezoidal Rule: Tn=2.413790T_n = 2.413790
  2. Midpoint Rule: Mn=2.411453M_n = 2.411453
  3. Simpson's Rule: Sn=2.412232S_n = 2.412232

Would you like more details or have any questions?

Here are five related questions you could explore next:

  1. How does increasing nn affect the accuracy of these approximations?
  2. What is the exact value of the integral and how close are these approximations to it?
  3. How do these rules compare for other functions, such as exponential or trigonometric functions?
  4. Can you use adaptive methods to improve the accuracy for specific intervals?
  5. How do Simpson's Rule and Trapezoidal Rule converge compared to the Midpoint Rule for this integral?

Tip: Simpson's Rule often provides a more accurate approximation than the Trapezoidal and Midpoint rules for smooth functions because it uses quadratic interpolations.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Numerical Integration
Approximation Techniques
Integral Calculus

Formulas

Trapezoidal Rule: T_n = (h / 2) * [f(x_0) + 2 * Σ f(x_i) + f(x_n)]
Midpoint Rule: M_n = h * Σ f((x_(i-1) + x_i) / 2)
Simpson's Rule: S_n = (h / 3) * [f(x_0) + 4 * Σ f(x_odd) + 2 * Σ f(x_even) + f(x_n)]

Theorems

Simpson's Rule
Trapezoidal Rule
Midpoint Rule

Suitable Grade Level

College Calculus or Advanced High School (Grades 11-12)