Math Problem Statement
Solution
Let us solve each of the given problems step by step.
(iii) Problem
If denotes the number of positive divisors of , then ?
Solution:
To determine , we first find the prime factorization of :
The formula to compute the number of divisors is: where are the exponents of the prime factors.
For , the exponents are and . So:
Thus, .
Answer:
(iv) Problem
If is an integer, then ?
Solution:
Here, represents the greatest integer less than or equal to (floor function). Let's analyze the behavior:
-
If is positive: [ [x] = x, \quad [-x] = -x - 1 \quad (\text{since } -x \text{ is negative, and we floor it to the next lower integer}). ] Therefore: [ [x] + [-x] = x + (-x - 1) = -1 ]
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If is negative: [ [x] = x, \quad [-x] = -x \quad (\text{since } -x \text{ is positive, and the floor is just } -x). ] Therefore: [ [x] + [-x] = x + (-x) = -1 ]
In both cases, .
Answer:
(v) Problem
If , then a linear Diophantine equation has a solution if and only if:
Solution:
The linear Diophantine equation has a solution if and only if the greatest common divisor () of and , which is , divides . That is:
This is a standard result from number theory.
Answer:
Final Answers:
- (iii):
- (iv):
- (v):
Would you like detailed explanations or further clarification on any of these problems?
Related Questions:
- How do you calculate the number of divisors for any number using its prime factorization?
- What are the properties of the floor function for different types of numbers?
- Why does ensure that a Diophantine equation has a solution?
- Can there be multiple solutions to ? How do you find them?
- How would the solution to change if were not an integer?
Tip:
The formula for the number of divisors is powerful and can also help find the sum and product of all divisors when combined with other number-theoretic tools!
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Math Problem Analysis
Mathematical Concepts
Number Theory
Prime Factorization
Floor Function
Linear Diophantine Equations
Formulas
d(n) = (e1 + 1)(e2 + 1)...(ek + 1) for prime factorization
[x] + [-x] = -1 for integers x
gcd(a, b) | c ensures ax + by = c has a solution
Theorems
Divisor Counting Formula
Greatest Common Divisor (gcd) Theorem for Diophantine Equations
Suitable Grade Level
Grade 10-12
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