Math Problem Statement

If d(n) denotes the number of positive divisors of n, then d(12) = ? (iii) If x is an integer then [x] + [-x] = ? (iv) If (a, b) = g, then a linear Diophantine equation ax + by = c has a solution if and only if ? (v)

Solution

Let us solve each of the given problems step by step.


(iii) Problem

If d(n)d(n) denotes the number of positive divisors of nn, then d(12)=d(12) = ?

Solution:

To determine d(12)d(12), we first find the prime factorization of 1212: 12=223112 = 2^2 \cdot 3^1

The formula to compute the number of divisors is: d(n)=(e1+1)(e2+1)(ek+1)d(n) = (e_1 + 1)(e_2 + 1)\ldots(e_k + 1) where e1,e2,,eke_1, e_2, \ldots, e_k are the exponents of the prime factors.

For 12=223112 = 2^2 \cdot 3^1, the exponents are 22 and 11. So: d(12)=(2+1)(1+1)=32=6d(12) = (2 + 1)(1 + 1) = 3 \cdot 2 = 6

Thus, d(12)=6d(12) = 6.

Answer: b)6b) \, 6


(iv) Problem

If xx is an integer, then [x]+[x]=[x] + [-x] = ?

Solution:

Here, [x][x] represents the greatest integer less than or equal to xx (floor function). Let's analyze the behavior:

  1. If xx is positive: [ [x] = x, \quad [-x] = -x - 1 \quad (\text{since } -x \text{ is negative, and we floor it to the next lower integer}). ] Therefore: [ [x] + [-x] = x + (-x - 1) = -1 ]

  2. If xx is negative: [ [x] = x, \quad [-x] = -x \quad (\text{since } -x \text{ is positive, and the floor is just } -x). ] Therefore: [ [x] + [-x] = x + (-x) = -1 ]

In both cases, [x]+[x]=1[x] + [-x] = -1.

Answer: d)1d) \, -1


(v) Problem

If (a,b)=g(a, b) = g, then a linear Diophantine equation ax+by=cax + by = c has a solution if and only if:

Solution:

The linear Diophantine equation ax+by=cax + by = c has a solution if and only if the greatest common divisor (gcd\text{gcd}) of aa and bb, which is gg, divides cc. That is: gcg \mid c

This is a standard result from number theory.

Answer: c)gcc) \, g \mid c


Final Answers:

  • (iii): b)6b) \, 6
  • (iv): d)1d) \, -1
  • (v): c)gcc) \, g \mid c

Would you like detailed explanations or further clarification on any of these problems?


Related Questions:

  1. How do you calculate the number of divisors for any number using its prime factorization?
  2. What are the properties of the floor function [x][x] for different types of numbers?
  3. Why does gcg \mid c ensure that a Diophantine equation has a solution?
  4. Can there be multiple solutions to ax+by=cax + by = c? How do you find them?
  5. How would the solution to [x]+[x][x] + [-x] change if xx were not an integer?

Tip:

The formula for the number of divisors d(n)d(n) is powerful and can also help find the sum and product of all divisors when combined with other number-theoretic tools!

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Math Problem Analysis

Mathematical Concepts

Number Theory
Prime Factorization
Floor Function
Linear Diophantine Equations

Formulas

d(n) = (e1 + 1)(e2 + 1)...(ek + 1) for prime factorization
[x] + [-x] = -1 for integers x
gcd(a, b) | c ensures ax + by = c has a solution

Theorems

Divisor Counting Formula
Greatest Common Divisor (gcd) Theorem for Diophantine Equations

Suitable Grade Level

Grade 10-12