Math Problem Statement

Differentiate e^x cos^4x for nth derivative

Solution

To find the nn-th derivative of the function f(x)=excos4(x)f(x) = e^x \cos^4(x), we need to understand the general pattern that emerges after applying the differentiation process repeatedly.

Step-by-Step Process:

  1. First Derivative: Let's begin by applying the product rule to differentiate f(x)=excos4(x)f(x) = e^x \cos^4(x): f(x)=excos4(x)+exddx(cos4(x)).f'(x) = e^x \cos^4(x) + e^x \frac{d}{dx}(\cos^4(x)). We need to calculate the derivative of cos4(x)\cos^4(x).

  2. Derivative of cos4(x)\cos^4(x): Use the chain rule: ddx(cos4(x))=4cos3(x)(sin(x))=4cos3(x)sin(x).\frac{d}{dx}(\cos^4(x)) = 4\cos^3(x) \cdot (-\sin(x)) = -4\cos^3(x) \sin(x).

  3. First Derivative (Complete): Now substitute back: f(x)=excos4(x)4excos3(x)sin(x).f'(x) = e^x \cos^4(x) - 4e^x \cos^3(x) \sin(x). Factor out exe^x: f(x)=ex(cos4(x)4cos3(x)sin(x)).f'(x) = e^x (\cos^4(x) - 4\cos^3(x) \sin(x)).

  4. General Pattern: Notice that exe^x appears in each term, and the derivative involves differentiating powers of trigonometric functions. This suggests that after the nth derivative, the expression will be of the form: f(n)(x)=exPn(cos(x),sin(x)),f^{(n)}(x) = e^x P_n(\cos(x), \sin(x)), where Pn(cos(x),sin(x))P_n(\cos(x), \sin(x)) is a polynomial in cos(x)\cos(x) and sin(x)\sin(x) with terms that depend on nn. The structure of the polynomial will involve alternating between products of cos(x)\cos(x) and sin(x)\sin(x), and the powers will evolve as a result of repeated differentiation.

Conclusion:

The nth derivative will take the form: f(n)(x)=exPn(cos(x),sin(x)),f^{(n)}(x) = e^x P_n(\cos(x), \sin(x)), where Pn(cos(x),sin(x))P_n(\cos(x), \sin(x)) is a polynomial generated through repeated product rule and chain rule applications.

Would you like more details on the general form of Pn(cos(x),sin(x))P_n(\cos(x), \sin(x)) or the derivation for specific small nn values?


5 Related Questions:

  1. How does the Leibniz rule for the nth derivative of a product apply in this case?
  2. How can we compute the nth derivative of cosn(x)\cos^n(x) in isolation?
  3. What role does the exponential factor exe^x play in simplifying the derivative process?
  4. How does trigonometric differentiation affect the pattern in successive derivatives?
  5. Can we use series expansion to approximate the nth derivative of excos4(x)e^x \cos^4(x)?

Tip: When differentiating products of functions, always look for patterns in the terms produced by applying the product rule recursively.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Trigonometric Functions
Exponential Functions
Nth Derivative

Formulas

Product Rule: (fg)' = f'g + fg'
Chain Rule: d/dx[f(g(x))] = f'(g(x)) * g'(x)
Derivative of cos^n(x): d/dx[cos^n(x)] = -n * cos^(n-1)(x) * sin(x)

Theorems

Leibniz Rule for the nth Derivative of a Product

Suitable Grade Level

Grades 11-12 and above