Math Problem Statement

What is nth derivatives of y =e^xcos^4x

Solution

To find the nth derivative of the function y=excos4(x)y = e^x \cos^4(x), we'll need to differentiate the product of these two functions multiple times.

Step 1: First derivative

We use the product rule for differentiation: ddx(uv)=uv+uv\frac{d}{dx}(uv) = u'v + uv' where u=exu = e^x and v=cos4(x)v = \cos^4(x).

First, differentiate each term:

  • The derivative of exe^x is exe^x.
  • To differentiate cos4(x)\cos^4(x), apply the chain rule: ddx(cos4(x))=4cos3(x)(sin(x))=4cos3(x)sin(x).\frac{d}{dx}(\cos^4(x)) = 4\cos^3(x) \cdot (-\sin(x)) = -4\cos^3(x) \sin(x).

Now, apply the product rule: y=ex(4cos3(x)sin(x))+excos4(x).y' = e^x \cdot (-4\cos^3(x) \sin(x)) + e^x \cos^4(x).

Factor out exe^x: y=ex[4cos3(x)sin(x)+cos4(x)].y' = e^x [-4\cos^3(x) \sin(x) + \cos^4(x)].

Step 2: Second derivative

For the second derivative, differentiate the first derivative again using the product rule. Let u=exu = e^x and v=4cos3(x)sin(x)+cos4(x)v = -4\cos^3(x) \sin(x) + \cos^4(x). You'll need to differentiate the trigonometric terms accordingly.

General Approach for nth derivative

Each differentiation will increase the complexity of the expression, involving terms with higher powers of sin(x)\sin(x) and cos(x)\cos(x) and possibly products of these with the exponential term exe^x. The nth derivative will follow a pattern involving the product rule applied repeatedly, and will alternate in signs and powers of trigonometric functions, with exponential growth due to exe^x.

Conclusion:

The nth derivative of y=excos4(x)y = e^x \cos^4(x) involves repeated applications of the product rule. The resulting pattern will always have exe^x factored out, with increasingly complex trigonometric terms involving powers of cos(x)\cos(x) and sin(x)\sin(x), and coefficients that come from the differentiation process.


Would you like a deeper dive into the second derivative or more on the general nth term? Feel free to ask!

Here are 5 related questions to expand on this topic:

  1. What is the second derivative of y=excos4(x)y = e^x \cos^4(x)?
  2. How does the Leibniz rule help in differentiating products multiple times?
  3. What is the pattern of coefficients in the nth derivative of excosn(x)e^x \cos^n(x)?
  4. Can we generalize the nth derivative for any product of exponential and trigonometric functions?
  5. How can Taylor series be used to approximate excos4(x)e^x \cos^4(x)?

Tip: When differentiating products, use the product rule and chain rule step by step to avoid errors, especially when dealing with higher derivatives.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Product Rule
Chain Rule
Exponential Functions
Trigonometric Functions

Formulas

Product Rule: (uv)' = u'v + uv'
Chain Rule: d/dx(f(g(x))) = f'(g(x)) * g'(x)
Derivative of e^x: d/dx(e^x) = e^x
Derivative of cos^n(x): d/dx(cos^n(x)) = -n*cos^(n-1)(x) * sin(x)

Theorems

Leibniz Rule for nth derivative of a product

Suitable Grade Level

University Level (Calculus II or higher)