Math Problem Statement

Los Angeles workers have an average commute of 29 minutes. Suppose the LA commute time is normally distributed with a standard deviation of 12 minutes. Let X represent the commute time for a randomly selected LA worker. Round all answers to 4 decimal places where possible. a. What is the distribution of X? b. Find the probability that a randomly selected LA worker has a commute that is longer than 30 minutes. c. Find the 90th percentile for the commute time of LA workers.

Solution

Let's break down the questions based on the image you provided:

a. What is the distribution of XX?

This part asks for the distribution of XX, where XX represents the commute time for LA workers. The normal distribution is typically written as:

XN(μ,σ2)X \sim N(\mu, \sigma^2)

where:

  • μ\mu is the mean commute time (29 minutes),
  • σ\sigma is the standard deviation (12 minutes).

Thus, the distribution is:

XN(29,122)X \sim N(29, 12^2)

b. Find the probability that a randomly selected LA worker has a commute that is longer than 30 minutes.

This is a probability question asking for P(X>30)P(X > 30), where XN(29,122)X \sim N(29, 12^2).

  1. First, we calculate the Z-score: Z=Xμσ=302912=1120.0833Z = \frac{X - \mu}{\sigma} = \frac{30 - 29}{12} = \frac{1}{12} \approx 0.0833
  2. Now, we use the Z-score to find the probability using standard normal distribution tables or a calculator.

P(Z>0.0833)P(Z > 0.0833)

Using a Z-table or a calculator, we find that: P(Z>0.0833)0.4660P(Z > 0.0833) \approx 0.4660

So, the probability that a worker has a commute longer than 30 minutes is approximately 0.46600.4660 or 46.60%.

c. Find the 90th percentile for the commute time of LA workers.

The 90th percentile corresponds to a Z-score of approximately 1.2816 (from standard normal tables).

We use the formula for the Z-score: X=μ+ZσX = \mu + Z \cdot \sigma Substituting the known values: X=29+1.28161229+15.379244.3792X = 29 + 1.2816 \cdot 12 \approx 29 + 15.3792 \approx 44.3792

So, the 90th percentile commute time is approximately 44.3792 minutes.


Would you like more details on any of these steps?

Five related questions:

  1. How do we interpret the result of a normal distribution in real-life scenarios?
  2. What is the significance of the Z-score in calculating probabilities?
  3. How can we use the 68-95-99.7 rule in understanding normal distributions?
  4. How do we find the 50th percentile of a normal distribution?
  5. What is the difference between a probability and a percentile in statistics?

Tip:

Always remember to check if your distribution is normal before applying Z-scores. Normality is essential for the correct use of Z-tables!

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Math Problem Analysis

Mathematical Concepts

Normal Distribution
Z-Scores
Percentiles

Formulas

Z = (X - μ) / σ
X = μ + Z * σ

Theorems

Empirical Rule (68-95-99.7)
Standard Normal Distribution

Suitable Grade Level

High School or Early College (Grades 11-12 or College-Level)