Math Problem Statement
resolver
Solution
The problem involves a modified Newton's rings setup, which involves interference by reflection. We're given three indices of refraction , , and . The task is to find the three minimum values of the air gap thickness that result in a maximum intensity at the center when illuminated with light of wavelength .
Step-by-step Solution:
When light reflects off a thin film between two different media, constructive interference (a maximum) occurs when the optical path difference is an integer multiple of the wavelength:
where:
- (refractive index of the medium where the interference happens),
- is the air gap or thickness,
- is the order of the fringe (an integer ),
- is the wavelength of the light.
Since the problem asks for the first three minimum values of , we will calculate for .
Let's calculate the values for :
Now, let's compute the three values.The three minimum values of the air gap thickness that result in a maximum at the center are:
- For : (which corresponds to the surfaces being in contact)
- For :
- For :
Would you like a more detailed explanation, or do you have any questions?
Related Questions
- How does the refractive index affect the formation of Newton's rings?
- What would happen if the wavelength of light was changed to a different value?
- How do destructive interference patterns differ from constructive interference in this setup?
- What is the significance of the phase change on reflection in Newton's rings?
- How would the shape of the rings change if and were different?
Tip: Remember that in optics, the phase change upon reflection depends on whether light reflects off a medium with a higher or lower refractive index.
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Math Problem Analysis
Mathematical Concepts
Optics
Wave Interference
Thin Film Interference
Formulas
2 n_2 d_0 = m λ
d_0 = m λ / (2 n_2)
Theorems
Thin Film Interference for Constructive Interference
Newton's Rings
Suitable Grade Level
University - Intermediate Physics
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