Math Problem Statement
Solution
To solve the given problem, let's break it down step-by-step.
Given Data:
- Incident angle:
- Wavelength : (green light)
- Order of interference:
- Refractive index :
Part (a): Thickness of the liquid film
When light reflects from a thin film, interference conditions apply. The reflected light undergoes a phase change, and constructive interference occurs when:
Plugging in the given values:
Calculating :
We solve for :
Now, let's compute it:
Thus, the thickness of the liquid film is approximately 316 nm.
Part (b): Wavelength and color for normal incidence
For normal incidence (), the interference condition simplifies to:
Using the thickness and :
Calculating :
This wavelength () corresponds to infrared light, which is not visible to the human eye.
Summary of Answers
- (a) The thickness of the liquid film is 316 nm.
- (b) The wavelength of the reflected light at normal incidence is 841 nm (infrared light).
Do you need further details or clarifications?
Related Questions:
- How does the interference condition change if the refractive index changes?
- What happens if the angle increases beyond ?
- How does the order affect the thickness calculation?
- Can destructive interference be used to determine the thickness?
- What other colors can appear due to thin-film interference?
Tip:
In thin-film interference, constructive and destructive interference depend on both the film's thickness and the incident angle. Adjusting either can produce different colors.
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Math Problem Analysis
Mathematical Concepts
Optics
Interference of Light
Thin Film Interference
Formulas
2d n cos(α) = m λ (constructive interference)
2d n = m λ (for normal incidence)
Theorems
Interference Conditions in Thin Films
Suitable Grade Level
Grades 10-12 or early university level (Physics/Optics)
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