Math Problem Statement

Find the direction and magnitude of the net electrostatic force exerted on the point charge q2 in the figure. Let q=+2.3μ, and d=31cm. what is the direction (θ) in ∘ counterclockwise from q2-q3 direction

Find the direction and magnitude of the net electrostatic force exerted on the point charge q2 in the figure. Let q = +2.3μC, and d = 31cm. What is the direction (θ) in degrees counterclockwise from the q2-q3 direction?

Solution

To find the direction and magnitude of the net electrostatic force on charge q2q_2 in the given square arrangement of charges, we can use Coulomb's Law. The charges are arranged in a square, and we need to find the individual forces between q2q_2 and the other charges q1,q3,q4q_1, q_3, q_4, and then sum them vectorially.

Given:

  • q=+2.3μCq = +2.3 \, \mu C
  • d=31cm=0.31md = 31 \, cm = 0.31 \, m
  • The charges at the corners:
    • q1=+q=+2.3μCq_1 = +q = +2.3 \, \mu C
    • q2=2q=4.6μCq_2 = -2q = -4.6 \, \mu C
    • q3=3q=6.9μCq_3 = -3q = -6.9 \, \mu C
    • q4=4q=9.2μCq_4 = -4q = -9.2 \, \mu C

Steps:

  1. Coulomb's Law: The magnitude of the force between two charges is given by Coulomb's Law: F=kq1q2r2F = k \frac{|q_1 q_2|}{r^2} where:

    • k=8.99×109Nm2/C2k = 8.99 \times 10^9 \, N \cdot m^2/C^2 (Coulomb constant),
    • q1q_1 and q2q_2 are the magnitudes of the charges,
    • rr is the distance between the charges.
  2. Force between q2q_2 and q3q_3: The distance between q2q_2 and q3q_3 is d=0.31md = 0.31 \, m. The force is attractive since they have opposite charges. The direction will be along the line connecting q2q_2 and q3q_3.

  3. Force between q2q_2 and q1q_1: The distance between q2q_2 and q1q_1 is also d=0.31md = 0.31 \, m. The force is repulsive since they have opposite signs, and the force direction will be along the line connecting q2q_2 and q1q_1.

  4. Force between q2q_2 and q4q_4: The diagonal distance between q2q_2 and q4q_4 is 2d\sqrt{2}d. Again, they have opposite charges, so the force will be attractive along the diagonal.

  5. Vector components: Once the magnitudes are calculated, we can decompose the forces into their components along the x and y axes and sum them to find the resultant net force. The angle θ\theta counterclockwise from the q2q_2-q3q_3 axis can then be determined using trigonometry.

I'll calculate the forces next.The magnitude of the net electrostatic force exerted on charge q2q_2 is approximately 4.39N4.39 \, N.

The direction of this net force is θ5.36\theta \approx 5.36^\circ counterclockwise from the q2q_2-q3q_3 direction (horizontal axis).

Would you like further details or explanations on how the forces were calculated or how the components were handled?

Here are 5 related questions that expand on this:

  1. How would the forces change if the distances between the charges were doubled?
  2. What would happen to the net force direction if charge q1q_1 were negative instead of positive?
  3. How can you generalize this method for charges arranged in a different geometric shape, such as a triangle?
  4. How do electric field lines behave in the vicinity of multiple charges like these?
  5. How does the principle of superposition help in calculating forces in systems with multiple charges?

Tip: Always break forces into components when dealing with non-aligned vectors to simplify vector addition.

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Math Problem Analysis

Mathematical Concepts

Electrostatics
Vector Addition
Coulomb's Law
Trigonometry

Formulas

F = k * |q1 * q2| / r^2
Vector Decomposition
Pythagorean Theorem
Trigonometric Ratios

Theorems

Coulomb's Law
Principle of Superposition

Suitable Grade Level

Undergraduate Physics