To perform the operation $-8i(9 + 3i)$, we will use the distributive property to multiply the terms.

$-8i(9 + 3i) = -8i \cdot 9 + (-8i \cdot 3i)$

Now, let's compute each term:

1. $-8i \cdot 9 = -72i$
2. $-8i \cdot 3i = -24i^2$

Since $i^2 = -1$, we substitute $-1$ for $i^2$:

$-24i^2 = -24(-1) = 24$

Now, combine both terms:

$-72i + 24$

The result in standard form is:

$24 - 72i$

Would you like a more detailed breakdown, or do you have any questions?

Here are 5 related questions:

1. What is the result of multiplying $5i(7 - 2i)$?
2. Can you expand $(3 + 4i)(1 - 5i)$ and write the result in standard form?
3. What is $i^3$ and $i^4$ in terms of $i$?
4. How do you find the magnitude of a complex number like $24 - 72i$?
5. How can complex numbers be represented on the complex plane?

Tip: When multiplying complex numbers, always remember that $i^2 = -1$, which simplifies the imaginary unit calculations!