Math Problem Statement

Имеется два сплава. Первый сплав содержит 5% меди, второй — 14% меди. Масса второго сплава больше массы первого на 10 кг. Из этих двух сплавов получили третий сплав, содержащий 12% меди. Найдите массу третьего сплава. Ответ дайте в килограммах.

Solution

The problem in the image describes a mixture problem with alloys containing copper. Let's break it down and solve it step by step.

Problem Details:

  1. First alloy contains 5% copper.
  2. Second alloy contains 14% copper, and its mass is 10 kg greater than the mass of the first alloy.
  3. These two alloys are mixed to create a third alloy containing 12% copper.
  4. Find the mass of the third alloy, with the answer in kilograms.

Step 1: Define Variables

Let:

  • xx: Mass of the first alloy (in kilograms),
  • x+10x + 10: Mass of the second alloy (since it is 10 kg heavier than the first alloy),
  • M=x+(x+10)M = x + (x + 10): Total mass of the third alloy (sum of the masses of the first and second alloys).

Step 2: Copper Content in Each Alloy

  • Copper in the first alloy: 0.05x0.05x,
  • Copper in the second alloy: 0.14(x+10)0.14(x + 10),
  • Copper in the third alloy: 0.12M0.12M.

Step 3: Balance Equation for Copper

The total copper in the third alloy comes from the copper in the first and second alloys: 0.05x+0.14(x+10)=0.12(x+(x+10)).0.05x + 0.14(x + 10) = 0.12(x + (x + 10)).


Step 4: Expand and Simplify

Expand the terms: 0.05x+0.14x+1.4=0.12(2x+10).0.05x + 0.14x + 1.4 = 0.12(2x + 10). Simplify: 0.19x+1.4=0.24x+1.2.0.19x + 1.4 = 0.24x + 1.2.


Step 5: Solve for xx

Rearrange terms: 1.41.2=0.24x0.19x,1.4 - 1.2 = 0.24x - 0.19x, 0.2=0.05x.0.2 = 0.05x. Solve for xx: x=0.20.05=4kg.x = \frac{0.2}{0.05} = 4 \, \text{kg}.


Step 6: Find the Total Mass of the Third Alloy

The first alloy weighs x=4kgx = 4 \, \text{kg}, and the second alloy weighs x+10=14kgx + 10 = 14 \, \text{kg}. Therefore, the mass of the third alloy is: M=4+14=18kg.M = 4 + 14 = 18 \, \text{kg}.


Final Answer:

The mass of the third alloy is 18 kilograms.

Would you like a detailed explanation of any step, or do you have any questions? 😊


Follow-Up Questions:

  1. What is the proportion of copper in the first alloy compared to the third?
  2. If the second alloy was only 5 kg heavier than the first, how would the solution change?
  3. What would happen if the percentage of copper in the third alloy increased to 15%?
  4. How can this problem be generalized for nn alloys?
  5. Can you formulate the problem as a system of equations in terms of total masses?

Tip:

In mixture problems, always set up a clear equation for the conserved quantity—in this case, the copper content.

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Math Problem Analysis

Mathematical Concepts

Algebra
Percentage Calculations
Mixtures and Alloys

Formulas

Mass of third alloy: M = mass of first alloy + mass of second alloy
Conservation of copper content: copper in first alloy + copper in second alloy = copper in third alloy

Theorems

Conservation Principle (applied to copper content)

Suitable Grade Level

Grades 8-10