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The problem shows that Nate wants to mix blue and yellow paint in a ratio of **1:3** (blue to yellow), and he needs a total of **8 gallons** of paint.

Since the ratio of blue to yellow is **1:3**, for every 1 part of blue paint, he needs 3 parts of yellow paint. Together, this makes a total of **4 parts** (1 part blue + 3 parts yellow).

We need to divide the 8 gallons of paint into these 4 parts:

\[
\text{Each part} = \frac{8}{4} = 2 \, \text{gallons}
\]

Now, Nate will need **3 parts** of yellow paint. Therefore, the amount of yellow paint he needs is:

\[
3 \times 2 = 6 \, \text{gallons}
\]

Thus, Nate needs to buy **6 gallons** of yellow paint. 

Would you like more details on this problem? 

Here are 5 related questions to further your understanding:
1. How much blue paint does Nate need to buy?
2. If the ratio were 2:3 instead, how much yellow paint would Nate need?
3. What would happen if Nate only needed 4 gallons of paint in total?
4. How would the total amount of paint change if Nate used a 2:1 ratio of blue to yellow instead?
5. How can we verify that the total amount of paint (blue + yellow) adds up correctly?

**Tip:** When working with ratios, always sum the parts to figure out the total amount each part represents.

Nate is helping to redesign his basement. He is in charge of choosing and buying the paint. He wants a specific shade of green, so he is going to combine blue and yellow paint in the ratio of 1:3. If he needs 8 gallons of paint, how much yellow paint does he need to buy?

Learn how to calculate the amount of yellow paint needed when mixing blue and yellow paint in a 1:3 ratio to create 8 gallons of paint. This problem covers key ratio and proportion concepts, making it perfect for students in Grades 5-7.

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