16 litres of yellow paint and 28 litres of blue paint make 44 litres of green paint, if you use 28 litres of yellow paint, how much blue paint do you need to get the same shade of green

To solve this problem, we can use a simple ratio method since the ratio of yellow paint to blue paint must remain the same to maintain the same shade of green.

The original ratio of yellow to blue paint is:

\[
\frac{16 \, \text{litres of yellow}}{28 \, \text{litres of blue}} = \frac{16}{28} = \frac{4}{7}
\]

This means for every 4 litres of yellow paint, 7 litres of blue paint are required. Now, if you are using 28 litres of yellow paint, we can set up a proportion to find the required amount of blue paint \( x \):

\[
\frac{4}{7} = \frac{28}{x}
\]

Cross-multiply and solve for \( x \):

\[
4x = 7 \times 28
\]
\[
4x = 196
\]
\[
x = \frac{196}{4} = 49
\]

So, you would need **49 litres of blue paint** to maintain the same shade of green.

Would you like further details or clarifications on this? Here are some related questions for practice:

1. If you use 10 litres of yellow paint, how much blue paint would you need?
2. What is the total amount of paint needed if you use 28 litres of yellow and 49 litres of blue?
3. How would the amount of blue paint change if you used 32 litres of yellow paint?
4. What ratio of yellow to blue paint would be needed if you had only 20 litres of blue paint available?
5. How much green paint would you have if you used 20 litres of yellow and the corresponding amount of blue?

**Tip:** Ratios are very useful in problems involving mixtures—always keep proportions consistent for uniform results!

16 litres of yellow paint and 28 litres of blue paint make 44 litres of green paint, if you use 28 litres of yellow paint, how much blue paint do you need to get the same shade of green?

Learn how to calculate the required amount of blue paint when mixing with 28 litres of yellow paint to get the same shade of green. This problem involves the use of ratios and proportions, suitable for students in Grades 6-8. Includes detailed step-by-step solution.

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