Math Problem Statement
Solution
We are tasked with finding the minimum value of in the 12-digit number , which is divisible by 21.
Step 1: Divisibility by 21
A number divisible by 21 must be divisible by both 3 and 7. We will need to apply the rules of divisibility for both these numbers.
Divisibility by 3:
A number is divisible by 3 if the sum of its digits is divisible by 3. Let's calculate the sum of the known digits:
Let and be the digits to be determined. The total sum of the digits will be:
For divisibility by 3, we need:
Thus,
This equation will guide us when selecting values for and .
Divisibility by 7:
To check divisibility by 7, we use the complete number. We will try different values for and , making sure both divisibility rules are satisfied.
Step 2: Minimize
We want to minimize while ensuring the number is divisible by both 3 and 7. We will test combinations of and that satisfy the modulo conditions.
I'll compute this next to determine the minimal values.The possible values of and that satisfy the divisibility rules (by both 3 and 7) are:
- , with
- , with
- , with
- , with
- , with
The minimum value of is 10, which occurs when and .
Would you like more details on how divisibility by 7 was checked, or have any other questions?
Related Questions:
- What is the rule for divisibility by 7, and how can it be applied quickly?
- How does the sum of digits help in checking divisibility by 3?
- Can have any other values for different divisibility conditions?
- How does changing one digit in a large number affect divisibility?
- What if the condition was divisibility by another number, like 11 or 13?
Tip:
When checking divisibility by 7, you can break large numbers into smaller chunks and apply modular arithmetic to simplify the process.
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Math Problem Analysis
Mathematical Concepts
Divisibility Rules
Modular Arithmetic
Number Theory
Formulas
Divisibility Rule for 3: Sum of digits divisible by 3
Divisibility Rule for 7: Complex divisibility rule requiring calculations
Theorems
Divisibility Theorems
Suitable Grade Level
Grades 9-12