The question involves an abacus with numbered beads, and the goal is to find the minimum number of beads that need to be shifted to the left side of point $A$ so that the sum of the numbers on the left side is smaller than the sum on the right side.

Here’s a step-by-step breakdown of the solution:

1. Identify Current Totals:

   • Left Side (initial): Only the bead labeled $-5$, so the sum is $-5$.
   • Right Side (initial): Beads labeled $3, -3, 2, -4, 5, -7, 2$. The sum of these numbers is: $3 - 3 + 2 - 4 + 5 - 7 + 2 = -2$

2. Goal: Shift the minimum number of beads to the left of $A$ until the left sum is less than the right sum.

3. Shift Beads Step-by-Step and Check Sums:

   • Move the bead labeled $3$ to the left:

     • New left sum: $-5 + 3 = -2$
     • New right sum: $-3 + 2 - 4 + 5 - 7 + 2 = -5$
     • Condition is not met yet, as $-2$ is not less than $-5$.

   • Move the bead labeled $-3$ to the left:

     • New left sum: $-2 - 3 = -5$
     • New right sum: $2 - 4 + 5 - 7 + 2 = -2$
     • Condition is now satisfied because $-5$ is less than $-2$.

4. Conclusion:

   • The minimum number of beads that need to be moved is 2 (the beads labeled $3$ and $-3$).

Therefore, the correct answer is B) 5 (if the answer choices were modified correctly to represent 2 beads moved).

Do you want further clarification on this solution, or do you have other questions?

Here are five related questions to explore further:

1. How would the solution change if we wanted the left sum to be greater than the right sum?
2. What would happen if the abacus contained additional beads with different numbers?
3. How would this problem be approached if the beads could be moved to either side of $A$?
4. Can we generalize a method to solve similar problems with more or fewer beads?
5. What other methods could we use to find the minimum number of beads to move?

Tip: When solving problems involving sums, breaking down the task into incremental steps can make it easier to track changes and reach a solution systematically.