Math Problem Statement
Solution
The problem you have uploaded involves finding the minimum total cost by determining the number of units to be produced on two machines, A and B, given their respective cost functions and a constraint on the total number of units produced.
Step-by-step breakdown:
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Cost Function of Machine A: where is the number of units produced on machine A.
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Cost Function of Machine B: where is the number of units produced on machine B.
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Total Cost Function: The total cost is given by:
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Constraint: The total number of units required is .
Goal:
To minimize the total cost , we need to determine how many units should be produced on machine A and how many units should be produced on machine B.
Solving the problem:
To solve this, we need to apply optimization techniques. First, substitute into the total cost function, and then differentiate the cost with respect to and set the derivative equal to zero to find the minimum.
Let me calculate that for you.The minimum total cost is achieved when 12,100 units are produced on machine A and 110 units are produced on machine B.
Would you like further details on the steps taken to solve this?
Here are 5 related questions to explore:
- How is the derivative used to minimize a function?
- Why do we substitute into the total cost equation?
- What are the conditions for a function to have a minimum?
- Can the same technique be used if the cost functions were more complex?
- How do different constraints affect the optimization process?
Tip: When minimizing or maximizing a function with constraints, substituting the constraint into the objective function helps reduce the number of variables to manage.
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Math Problem Analysis
Mathematical Concepts
Optimization
Differentiation
Cost Minimization
Formulas
Machine A cost function: C_A(x) = 30 + x^2 / 6
Machine B cost function: C_B(y) = 240 + y^3 / 9
Total cost: C(x, y) = C_A(x) + C_B(y)
Constraint: x + y = 12,210
Theorems
First-order condition for optimization (setting the derivative equal to zero)
Suitable Grade Level
Undergraduate Level - Calculus and Optimization