Math Problem Statement

This company makes two products product, C and product B. Each product passes through the steaming machine area, which is the chief constraint during production. Product C takes 15 minutes on the steaming machine and have a contribution margin per product of $16. product B takes 24 minutes on the cutting machine and has a contribution margin per product of $32. It’s assumed that this business has 4800 hours available on the machine to service minimum demand for each product of 3000 units. How many of each product should be made?

Solution

To determine how many units of each product should be produced, we need to solve this as a linear programming problem. The goal is to maximize the contribution margin while satisfying constraints on machine availability and minimum demand.


Let:

  • xx: the number of units of Product C produced.
  • yy: the number of units of Product B produced.

Constraints:

  1. Steaming Machine Time Constraint: Each product uses time on the steaming machine: 15x+24y4800 hours ×60=288,000 minutes.15x + 24y \leq 4800 \text{ hours } \times 60 = 288,000 \text{ minutes.}

  2. Minimum Demand Constraint: x3000,y3000.x \geq 3000, \quad y \geq 3000.

  3. Non-Negativity: x0,y0.x \geq 0, \quad y \geq 0.

Objective Function:

We want to maximize the total contribution margin: Maximize Z=16x+32y.\text{Maximize } Z = 16x + 32y.


Solving the Problem:

  1. Convert the time constraint into a usable inequality: 15x+24y288,000.15x + 24y \leq 288,000.

  2. Set the minimum demand constraints: x3000,y3000.x \geq 3000, \quad y \geq 3000.

  3. Solve the system to maximize Z=16x+32yZ = 16x + 32y.

Let’s calculate the feasible solution and the optimal allocation.from scipy.optimize import linprog

Coefficients for the objective function (negative for maximization)

c = [-16, -32] # Maximize 16x + 32y

Coefficients for inequality constraints (Ax <= b)

A = [ [15, 24], # Time constraint [-1, 0], # x >= 3000 (converted to -x <= -3000) [0, -1] # y >= 3000 (converted to -y <= -3000) ]

b = [288000, -3000, -3000] # Right-hand side values

Bounds for x and y (x >= 3000, y >= 3000)

x_bounds = (3000, None) y_bounds = (3000, None)

Solve the linear programming problem

result = linprog(c, A_ub=A, b_ub=b, bounds=[x_bounds, y_bounds], method="highs")

Extract results

result.x, result.fun(array([ 3000., 10125.]), -372000.0)(array([ 3000., 10125.]), -372000.0)successThe optimal production plan is:

  • Produce 3,000 units of Product C.
  • Produce 10,125 units of Product B.

This maximizes the contribution margin to a value of $372,000.

Explanation:

  • The machine time constraint and minimum demand requirements are fully utilized to prioritize the product with a higher contribution margin (Product B).
  • You can now allocate resources effectively to achieve the best profitability within the constraints.

Would you like to review the detailed breakdown of the calculations or any adjustments? Here are some related questions to consider:

  1. How does the production plan change if the available machine hours increase?
  2. What happens if the minimum demand for Product C or B changes?
  3. How can the business increase its overall profitability under these constraints?
  4. What is the shadow price (marginal value) of an additional machine hour?
  5. How does changing the contribution margin for either product affect the solution?

Tip: Analyze the sensitivity of constraints to understand how small changes in machine time or demand affect profitability.

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Math Problem Analysis

Mathematical Concepts

Linear Programming
Optimization
Inequalities

Formulas

Objective Function: Z = 16x + 32y
Machine Time Constraint: 15x + 24y ≤ 288,000
Minimum Demand Constraints: x ≥ 3000, y ≥ 3000

Theorems

Linear Programming Optimality Theorem

Suitable Grade Level

Undergraduate (Introductory Operations Research or Advanced High School Math)