A triangle has vertices at A(2, —2), B(—4, —4), and C(O, 4).a) Draw the triangle, and determine the coordinates of the midpoints of its sides. 
b) Draw the median from vertex A, and determine its equation.

### a) **Draw the triangle and determine the coordinates of the midpoints of its sides.**

1. **Vertices of the triangle**:
   - \( A(2, -2) \)
   - \( B(-4, -4) \)
   - \( C(0, 4) \)

   To find the midpoints of each side, we'll use the midpoint formula. The midpoint \( M \) of two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by:

   \[
   M = \left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right)
   \]

2. **Midpoint of side \( AB \)**:
   - Using \( A(2, -2) \) and \( B(-4, -4) \):
     \[
     M_{AB} = \left( \frac{2 + (-4)}{2}, \frac{-2 + (-4)}{2} \right) = \left( \frac{-2}{2}, \frac{-6}{2} \right) = (-1, -3)
     \]

3. **Midpoint of side \( BC \)**:
   - Using \( B(-4, -4) \) and \( C(0, 4) \):
     \[
     M_{BC} = \left( \frac{-4 + 0}{2}, \frac{-4 + 4}{2} \right) = \left( \frac{-4}{2}, \frac{0}{2} \right) = (-2, 0)
     \]

4. **Midpoint of side \( AC \)**:
   - Using \( A(2, -2) \) and \( C(0, 4) \):
     \[
     M_{AC} = \left( \frac{2 + 0}{2}, \frac{-2 + 4}{2} \right) = \left( \frac{2}{2}, \frac{2}{2} \right) = (1, 1)
     \]

   Therefore, the midpoints of the sides are:
   - Midpoint of \( AB \): \( (-1, -3) \)
   - Midpoint of \( BC \): \( (-2, 0) \)
   - Midpoint of \( AC \): \( (1, 1) \)

### b) **Draw the median from vertex \( A \) and determine its equation.**

A **median** of a triangle is a line segment that joins a vertex to the midpoint of the opposite side. We will now determine the equation of the median from vertex \( A(2, -2) \) to the midpoint of side \( BC \), which we found to be \( (-2, 0) \).

1. **Find the slope of the median**:
   The slope \( m \) between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by:

   \[
   m = \frac{y_2 - y_1}{x_2 - x_1}
   \]

   Using \( A(2, -2) \) and \( (-2, 0) \):

   \[
   m = \frac{0 - (-2)}{-2 - 2} = \frac{2}{-4} = -\frac{1}{2}
   \]

2. **Equation of the median**:
   The equation of a line in point-slope form is:

   \[
   y - y_1 = m(x - x_1)
   \]

   Substituting \( m = -\frac{1}{2} \) and \( (x_1, y_1) = (2, -2) \):

   \[
   y - (-2) = -\frac{1}{2}(x - 2)
   \]
   Simplifying:
   \[
   y + 2 = -\frac{1}{2}x + 1
   \]
   \[
   y = -\frac{1}{2}x + 1 - 2
   \]
   \[
   y = -\frac{1}{2}x - 1
   \]

Thus, the equation of the median from vertex \( A \) is:
\[
y = -\frac{1}{2}x - 1
\]

### Summary:
- The midpoints of the sides are:
  - \( AB: (-1, -3) \)
  - \( BC: (-2, 0) \)
  - \( AC: (1, 1) \)
- The equation of the median from \( A \) to \( BC \) is:
  \[
  y = -\frac{1}{2}x - 1
  \]

Would you like me to provide more details or a diagram for this? 

Here are some follow-up questions to deepen your understanding:
1. What is the significance of the centroid in relation to the medians of a triangle?
2. How would you find the length of the median from vertex \( A \) to side \( BC \)?
3. Can you determine the equation of the other two medians in the triangle?
4. What are the properties of medians in an equilateral triangle?
5. How do the midpoints and the centroid of a triangle relate geometrically?

**Tip:** The point where the medians of a triangle intersect is called the **centroid**, which divides each median into a 2:1 ratio.

A triangle has vertices at A(2, —2), B(—4, —4), and C(O, 4). a) Draw the triangle, and determine the coordinates of the midpoints of its sides. b) Draw the median from vertex A, and determine its equation.

This problem involves determining the midpoints of the sides of a triangle with vertices A(2, -2), B(-4, -4), and C(0, 4), and finding the equation of the median from vertex A. The solution uses coordinate geometry concepts such as the midpoint formula and point-slope form. Suitable for students in Grades 9-10.

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