The midpoint of a line segment with endpoints $A(x_1, y_1)$ and $B(x_2, y_2)$ can be found using the midpoint formula:

$\text{Midpoint} = \left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right)$

For the points $A(-1, 7)$ and $B(5, 3)$, the midpoint $M$ is calculated as follows:

$M = \left(\frac{-1 + 5}{2}, \frac{7 + 3}{2}\right)$

Simplifying this:

$M = \left(\frac{4}{2}, \frac{10}{2}\right)$

$M = (2, 5)$

So, the midpoint of segment $AB$ is $(2, 5)$.

Would you like more details or have any questions?

Here are some related questions:

1. How do you find the distance between two points on a plane?
2. What is the slope of the line passing through points $A$ and $B$?
3. How do you find the equation of the line passing through points $A$ and $B$?
4. Can you find the area of the triangle formed by points $A$, $B$, and another point $C$?
5. How do you determine if three points are collinear?

Tip: When finding the midpoint, remember that it represents the average of the x-coordinates and y-coordinates of the endpoints.