Math Problem Statement
What is the maximum sending rate in Stop-and-wait technique if 1.5 Mbps link with 45ms round-trip time and frame size is 1KB
Solution
To calculate the maximum sending rate in the Stop-and-Wait ARQ technique, we use the following steps:
Formulas and Steps:
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Transmission Time (T_tx):
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Round Trip Time (RTT): Given directly in the problem.
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Maximum Sending Rate: The Stop-and-Wait protocol allows only one frame to be sent at a time, so the maximum sending rate is:
Given Data:
- Link speed () =
- Frame size () =
- RTT =
Step-by-Step Calculation:
Step 1: Calculate Transmission Time ():
Step 2: Compute Maximum Sending Rate:
Final Answer:
The maximum sending rate using the Stop-and-Wait technique is approximately:
Let me know if you need further clarifications! Below are some related questions for your practice:
Related Questions:
- How does the Stop-and-Wait protocol handle errors during transmission?
- What happens to efficiency as the frame size increases in Stop-and-Wait ARQ?
- How does RTT affect the overall throughput in Stop-and-Wait ARQ?
- What is the impact of using a higher link speed on the maximum sending rate?
- What are some real-world applications of the Stop-and-Wait protocol?
Tip:
For high-speed networks with significant RTT, Stop-and-Wait ARQ becomes inefficient. To improve performance, consider protocols like Sliding Window ARQ or Selective Repeat ARQ
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Math Problem Analysis
Mathematical Concepts
Data Transmission
Stop-and-Wait Protocol
Network Throughput
Formulas
Transmission Time: T_tx = Frame Size (bits) / Link Speed (bps)
Maximum Sending Rate: Max Rate = Frame Size (bits) / (RTT + T_tx)
Theorems
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Suitable Grade Level
Undergraduate (Computer Science / Networking)
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