Math Problem Statement
Consider a point-to-point link 4 km in length. At what bandwidth would propagation delay (at a speed of 2 × 108m/s) equal transmit delay for 100-byte packets What about 512-byte packets
Solution
To solve this, we need to equate the propagation delay and the transmit delay for different packet sizes.
Step 1: Propagation delay (T_prop)
The propagation delay is the time it takes for a signal to travel through the medium from the sender to the receiver.
where:
- (the distance of the link),
- (the propagation speed).
Step 2: Transmit delay (T_trans)
The transmit delay is the time it takes to put all the bits of the packet onto the wire.
where:
- is the size of the packet in bits,
- is the bandwidth in bits per second (bps).
Step 3: Equating the propagation delay and transmit delay
We want to find the bandwidth where .
Case 1: For 100-byte packets
- ,
- .
Case 2: For 512-byte packets
- ,
- .
Final Results:
- For 100-byte packets, the required bandwidth is 40 Mbps.
- For 512-byte packets, the required bandwidth is 204.8 Mbps.
Let me know if you need more details or have any questions!
Here are 5 related questions to deepen understanding:
- How would propagation delay change if the distance were halved?
- What happens to the transmit delay if packet size increases but bandwidth remains the same?
- How do different packet sizes affect overall latency on a network?
- What is the impact of higher bandwidth on the transmission delay for small packets?
- How does the speed of light in fiber optics compare to the given propagation speed?
Tip: Bandwidth affects how quickly data can be transmitted, but propagation delay depends solely on the distance and medium speed!
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Math Problem Analysis
Mathematical Concepts
Propagation Delay
Transmit Delay
Bandwidth
Packet Size
Formulas
Propagation delay (T_prop) = d / v
Transmit delay (T_trans) = L / B
Bandwidth (B) = L / T_prop
Theorems
-
Suitable Grade Level
Undergraduate Level (Telecommunications, Networking)
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