Math Problem Statement

. Show that the efficiency of power transfer is 50%, when the maximum power transfer occurs.

Solution

To show that the efficiency of power transfer is 50% when maximum power transfer occurs, we need to delve into the concept of maximum power transfer and the relationship between the power delivered to the load and the power supplied by the source.

Step 1: Maximum Power Transfer Theorem

The Maximum Power Transfer Theorem states that the maximum amount of power is transferred to the load when the load resistance (RLR_L) is equal to the source resistance (RSR_S).

That is: RL=RSR_L = R_S

Step 2: Power Delivered to the Load

Consider a circuit with a voltage source VV and a series combination of source resistance RSR_S and load resistance RLR_L. The total resistance in the circuit is RS+RLR_S + R_L.

The total current (II) in the circuit is given by Ohm's law: I=VRS+RLI = \frac{V}{R_S + R_L}

The power delivered to the load PLP_L is: PL=I2RLP_L = I^2 R_L

Substituting the expression for II: PL=(VRS+RL)2RLP_L = \left( \frac{V}{R_S + R_L} \right)^2 R_L

Step 3: Maximizing Power Delivered to the Load

To maximize the power delivered to the load, we differentiate PLP_L with respect to RLR_L and set the derivative equal to zero.

dPLdRL=ddRL(V2RL(RS+RL)2)\frac{dP_L}{dR_L} = \frac{d}{dR_L} \left( \frac{V^2 R_L}{(R_S + R_L)^2} \right)

This can be simplified, and when we set dPLdRL=0\frac{dP_L}{dR_L} = 0, we find that the power is maximized when: RL=RSR_L = R_S

Step 4: Efficiency of Power Transfer

The efficiency of power transfer η\eta is defined as the ratio of the power delivered to the load to the total power supplied by the source.

The total power supplied by the source is: Ptotal=I2RS=(VRS+RL)2RSP_{\text{total}} = I^2 R_S = \left( \frac{V}{R_S + R_L} \right)^2 R_S

When RL=RSR_L = R_S, we substitute this into the equation for PtotalP_{\text{total}}: Ptotal=(V2RS)2RS=V24RSP_{\text{total}} = \left( \frac{V}{2R_S} \right)^2 R_S = \frac{V^2}{4R_S}

Now, the efficiency η\eta is: η=PLPtotal=V24RSV24RS=12=50%\eta = \frac{P_L}{P_{\text{total}}} = \frac{\frac{V^2}{4R_S}}{\frac{V^2}{4R_S}} = \frac{1}{2} = 50\%

Conclusion:

Thus, the efficiency of power transfer is 50% when maximum power transfer occurs, which happens when RL=RSR_L = R_S.


Would you like more details or have any questions?

Here are some related questions you might find interesting:

  1. What happens to the efficiency if the load resistance is less than the source resistance?
  2. How can the maximum power transfer theorem be applied in electrical engineering design?
  3. What is the effect of varying the source voltage on power transfer efficiency?
  4. How does the efficiency change if RLR_L is greater than RSR_S?
  5. How can the efficiency be improved in practical circuits?

Tip: The Maximum Power Transfer Theorem is most useful when you want to maximize the power delivered to a load, but for energy efficiency, it's often better to design the circuit such that RLR_L is larger than RSR_S, to minimize losses.

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Math Problem Analysis

Mathematical Concepts

Circuit Theory
Power Transfer
Optimization

Formulas

I = V / (R_S + R_L)
P_L = I^2 R_L
P_total = I^2 R_S
Efficiency (eta) = P_L / P_total

Theorems

Maximum Power Transfer Theorem

Suitable Grade Level

Grades 11-12