Math Problem Statement
Suppose that X1,X2,…,Xn is a random sample from the exponential distribution with rate λ>0.
Find the MLE for P(X>1) where X is a future sampled value.
Solution
Given that is a random sample from the exponential distribution with rate , the probability density function (PDF) of is:
To find the maximum likelihood estimator (MLE) for where is a future sampled value, we start by identifying the parameter that maximizes the likelihood function based on the sample.
Step 1: Likelihood Function
The likelihood function for the sample is:
Step 2: Log-Likelihood Function
The log-likelihood function is:
Step 3: Maximizing the Log-Likelihood
To find the MLE of , we take the derivative of with respect to and set it to zero:
Solving for :
Step 4: Probability
For an exponential distribution with rate , the probability that a future sampled value exceeds 1 is:
This integral simplifies to:
Step 5: MLE for
We need the MLE for . Using the MLE for :
So, the MLE for is:
Would you like more details or have any questions about this solution?
Here are some related questions you might find useful:
- How is the exponential distribution used in reliability analysis?
- What is the relationship between the exponential and Poisson distributions?
- Can you explain the method of moments for parameter estimation?
- How does the exponential distribution relate to the memoryless property?
- What are the properties of the exponential distribution?
- How would the MLE change if we had a truncated sample?
- What are the advantages and limitations of using MLE?
- How do we construct confidence intervals for the rate parameter ?
Tip: When finding the MLE for any distribution, always start by writing down the likelihood function and proceed by taking the log to simplify the differentiation process.
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Math Problem Analysis
Mathematical Concepts
Exponential Distribution
Maximum Likelihood Estimation (MLE)
Probability Theory
Formulas
Exponential distribution PDF: f(x; \lambda) = \lambda e^{-\lambda x}, \quad x \geq 0
MLE for rate parameter: \hat{\lambda} = \frac{n}{\sum_{i=1}^n X_i}
Probability of survival function: P(X > 1) = e^{-\lambda}
Theorems
-
Suitable Grade Level
Advanced Undergraduate
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