A rectangle is measured to be 6cm by 8cm. Find the largest area it could have.

To maximize the area of a rectangle, you would typically consider varying dimensions. However, in this case, the rectangle's dimensions are fixed at 6 cm by 8 cm.

The area \( A \) of a rectangle is calculated using the formula:
\[
A = \text{length} \times \text{width}
\]
Substituting the given dimensions:
\[
A = 6 \, \text{cm} \times 8 \, \text{cm} = 48 \, \text{cm}^2
\]

Therefore, the largest possible area for this rectangle, given the dimensions, is **48 cm²**.

Would you like any more details, or do you have any further questions?

Here are five related questions to consider:
1. How would the area change if the dimensions were doubled?
2. What would the perimeter of this rectangle be?
3. How do you calculate the area of other shapes, like triangles or circles?
4. What is the formula for the diagonal length of this rectangle?
5. What happens to the area if one dimension is increased and the other is decreased?

**Tip:** Remember, the area of a shape is always expressed in square units, such as square centimeters (cm²).

Explore how to maximize the area of a rectangle with dimensions 6cm by 8cm. Learn the formula for calculating the area of a rectangle and how to apply it to find the largest possible area. Suitable for students in Grades 6-8.

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