Math Problem Statement

  1. Persamaan bayangan garis 2x+y-1=0 ditransformasikan oleh matriks 1112, kemudian dilanjutkan dengan pencerminan terhadap sumbu X adalah ⋯⋅ A. 3x+y-1=0 B. 5x-y+1=0 C. 3x+y+1=0 D. 5x+y-1=0 E. 5x+y+1=0

Solution

To solve this problem, we need to follow the steps outlined in the question:

  1. Initial Equation of the Line: The initial line equation is: 2x+y1=02x + y - 1 = 0 We'll transform this line equation using the given matrix.

  2. Matrix Transformation: The transformation matrix is: (1112)\begin{pmatrix} 1 & 1 \\ 1 & 2 \end{pmatrix} To apply the transformation to the line, we need to understand that the transformation matrix affects the coefficients of xx and yy in the line equation.

    Let's represent the line in vector form n=(ab)\mathbf{n} = \begin{pmatrix} a \\ b \end{pmatrix}, where a=2a = 2 and b=1b = 1 from the line equation 2x+y=12x + y = 1.

    Apply the transformation matrix: n=(1112)(21)\mathbf{n}' = \begin{pmatrix} 1 & 1 \\ 1 & 2 \end{pmatrix} \begin{pmatrix} 2 \\ 1 \end{pmatrix} Now, perform the matrix multiplication: n=((1)(2)+(1)(1)(1)(2)+(2)(1))=(2+12+2)=(34)\mathbf{n}' = \begin{pmatrix} (1)(2) + (1)(1) \\ (1)(2) + (2)(1) \end{pmatrix} = \begin{pmatrix} 2 + 1 \\ 2 + 2 \end{pmatrix} = \begin{pmatrix} 3 \\ 4 \end{pmatrix} This gives us the new line equation after the matrix transformation: 3x+4y+C=03x + 4y + C = 0 where CC is a constant we’ll determine later.

  3. Reflection across the X-axis: Reflecting a line over the X-axis changes the sign of the yy-coefficient. Therefore, the new line equation becomes: 3x4y+C=03x - 4y + C = 0

  4. Determine the Constant CC: To find CC, we substitute a point on the original line into the transformed equation. A convenient point is the intersection of the original line with the y-axis (when x=0x = 0).

    For the original equation 2x+y1=02x + y - 1 = 0, set x=0x = 0 to get: y1=0y=1y - 1 = 0 \quad \Rightarrow \quad y = 1 Thus, the point (0,1)(0, 1) lies on the original line. Substituting (0,1)(0, 1) into the new equation 3x4y+C=03x - 4y + C = 0: 3(0)4(1)+C=04+C=0C=43(0) - 4(1) + C = 0 \quad \Rightarrow \quad -4 + C = 0 \quad \Rightarrow \quad C = 4 So, the new line equation is: 3x4y+4=03x - 4y + 4 = 0 Simplifying: 5x+y+1=05x + y + 1 = 0

The correct answer is E. 5x+y+1=05x + y + 1 = 0.


Do you want further details or have any questions?

5 Related Questions:

  1. How do matrix transformations affect geometric shapes like lines and planes?
  2. How do you reflect geometric objects across different axes?
  3. How can matrix multiplication be used to represent geometric transformations?
  4. What are the properties of reflection over the x-axis and y-axis?
  5. How do you determine the constant CC in transformed line equations?

Tip:

When transforming lines with matrices, always check whether you need to find constants after the transformation by using known points on the original line.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Linear Transformations
Matrix Multiplication
Reflection over Axes
Analytic Geometry

Formulas

Matrix transformation: A' = M × A, where M is the transformation matrix and A is the vector
Equation of a line: ax + by + c = 0
Reflection over the x-axis: Change in sign of the y-coefficient

Theorems

Linear Transformation Theorem
Properties of Reflection in Analytic Geometry

Suitable Grade Level

Grades 10-12