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I see you've uploaded a set of math problems in Spanish. Let's work through them step by step.

### Problem 1:
It involves matrix multiplication to find total sales of refreshments and snacks over three months.

Matrix \( A \) (sales quantities for each month) and matrix \( B \) (unit prices for refreshments and snacks) are given as:

\[
A = \begin{pmatrix}
1500 & 2600 & 3650 \\
750 & 800 & 900
\end{pmatrix}
\quad B = \begin{pmatrix}
2.0 & 3.5 \\
1.5 & 3.0 \\
1.0 & 2.5
\end{pmatrix}
\]

The questions are:
- **(a)** Multiply the matrices to get total income from refreshments. Which element provides this information?
- **(b)** Multiply to get total monthly income. In which month was the maximum income achieved?
- **(c)** What was the total income over all three months?

### Steps:
1. Perform matrix multiplication \( C = A \times B \).
2. Analyze the elements of the resulting matrix \( C \).

Let's solve it:

\[
C = \begin{pmatrix}
1500 & 2600 & 3650 \\
750 & 800 & 900
\end{pmatrix}
\cdot
\begin{pmatrix}
2.0 & 3.5 \\
1.5 & 3.0 \\
1.0 & 2.5
\end{pmatrix}
\]

I’ll compute this step by step.After performing the matrix multiplication, we get the following result:

\[
C = \begin{pmatrix}
10550 & 22175 \\
3600 & 7275
\end{pmatrix}
\]

Where:
- The first row represents the income from **refreshments** for the months June, July, and August.
- The second row represents the income from **snacks** for the same months.

### Now, let's address each part of the problem:

#### (a) Multiply the matrices to obtain the income from selling refreshments in the three months.
- The **first element** of the matrix \( C \) (10550) corresponds to the income from **refreshments** in June. This information is given by the first element of the first row.
- The income from **snacks** is represented by the second row of the matrix.

#### (b) Which month had the maximum income?
- Total income from all products for each month can be calculated by summing the corresponding elements from both rows of \( C \):
  - June: \( 10550 + 3600 = 14150 \)
  - July: \( 22175 + 7275 = 29450 \)

The month with the highest income is **July** with 29,450 euros.

#### (c) What were the total sales across all three months?
The total income from refreshments and snacks for the three months is the sum of all elements in matrix \( C \):
\[
10550 + 22175 + 3600 + 7275 = 43500 \, \text{euros}.
\]

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Now, let's move on to **Problem 2**, which asks to find a function whose second derivative is \( -12x \) and whose graph has a minimum at the point \( (-2,0) \).

Would you like to proceed with solving Problem 2, or do you have any questions about Problem 1?

---

### 5 related questions:
1. How do you interpret the elements of a matrix multiplication result in business contexts like this one?
2. How would the solution change if the prices increased by 10%?
3. Could you identify which matrix multiplication property applies here?
4. How can this type of calculation be automated for a large supermarket chain with hundreds of products?
5. How does matrix multiplication apply in fields like economics or engineering?

### Tip:
In matrix multiplication, ensure that the dimensions of the matrices match properly, where the number of columns in the first matrix must equal the number of rows in the second matrix.

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