Math Problem Statement

Solve multiple mathematical problems involving circles, algebraic equations, and a cost formula for computers and printers.

Solution

Let's go over the math problems one by one. Here's a summary:

B. Circle problems:

  1. Find the circumference of a circle to the nearest tenth if the radius is 12 cm. The formula for circumference is C=2πrC = 2\pi r, where rr is the radius. Given r=12cmr = 12 \, \text{cm}, you have: C=2π×1275.4cmC = 2\pi \times 12 \approx 75.4 \, \text{cm}

  2. Find the area of a circle in terms of pi, if the diameter is 20 cm. The formula for the area of a circle is A=πr2A = \pi r^2. The radius rr is half the diameter, so: r=202=10cmr = \frac{20}{2} = 10 \, \text{cm} The area is: A=π×102=100πcm2A = \pi \times 10^2 = 100\pi \, \text{cm}^2

  3. Write an equation using rr for radius and dd for diameter that represents the relationship between radius and diameter. The relationship is simply: d=2rd = 2r or equivalently r=d2r = \frac{d}{2}.

F. Cost formula: You are asked to identify the correct formula for determining the number of printers purchased. The given formula is: T=581s+150pT = 581s + 150p where TT is the total cost, ss is the number of computers, and pp is the number of printers.

From the options:

  • A: p=T581s150p = \frac{T - 581s}{150} (Correct choice)
  • B: p=T581sp = T - 581s
  • C: p=T581s150p = \frac{T - 581s}{150} (Correct choice)
  • D: p=T581s150p = T - 581s - 150

G. Find the y-intercept: You need to find the y-intercept for the equations given.

  • For x5y=20x - 5y = -20, when x=0x = 0: 05y=20y=40 - 5y = -20 \quad \Rightarrow \quad y = 4

H. Solve the equations:

  1. (2x10)=3(x10)(2x - 10) = 3(x - 10) Solve step by step: 2x10=3(x10)2x - 10 = 3(x - 10) Expanding and solving: 2x10=3x302x - 10 = 3x - 30 2x3x=30+102x - 3x = -30 + 10 x=20x=20-x = -20 \quad \Rightarrow \quad x = 20

  2. 2(x10)=3(x10)-2(x - 10) = 3(x - 10) Follow a similar process to solve: 2(x10)=3(x10)-2(x - 10) = 3(x - 10) 2x+20=3x30-2x + 20 = 3x - 30 2x3x=3020-2x - 3x = -30 - 20 5x=50x=10-5x = -50 \quad \Rightarrow \quad x = 10

  3. x+23x154=0\frac{x + 2}{3} - \frac{x - 15}{4} = 0 Clear the denominators and solve: Multiply through by 12: 12(x+23x154)=0\text{Multiply through by 12: } 12\left(\frac{x + 2}{3} - \frac{x - 15}{4}\right) = 0 4(x+2)3(x15)=04(x + 2) - 3(x - 15) = 0 4x+83x+45=04x + 8 - 3x + 45 = 0 x=53x = -53

  4. 33(x12)=16(x+20)\frac{3}{3}(x - 12) = \frac{1}{6}(x + 20) Solve the equation: (x12)=12(x+20)(x - 12) = \frac{1}{2}(x + 20) 2(x12)=x+202(x - 12) = x + 20 2x24=x+202x - 24 = x + 20 x=44x = 44

Let me know if you'd like further explanation or if you have any specific questions!

5 related questions you might find useful:

  1. How do you calculate the surface area of a sphere given its radius?
  2. What is the difference between the area and circumference of a circle?
  3. How can you convert between different units of measurement for the circumference?
  4. How would you solve for the cost of a printer if given the total cost and number of computers?
  5. How do you find the equation of a line from two given points?

Tip: When solving equations involving fractions, it's often useful to clear the denominators by multiplying the entire equation by the least common denominator (LCD).

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Math Problem Analysis

Mathematical Concepts

Geometry: Circles (Circumference and Area)
Algebra: Solving linear equations
Linear Relationships
Word Problems: Cost analysis using formulas

Formulas

Circumference of a circle: C = 2πr
Area of a circle: A = πr²
Linear equations: y = mx + b
Total cost formula: T = 581s + 150p

Theorems

Properties of circles
Linear equation solutions
Basic proportional relationships in algebra

Suitable Grade Level

Grades 7-10