Math Problem Statement

Match each function f(x) with its corresponding derivative f'(x) from the given options.

Solution

Let's solve the given derivative problems step by step by matching the function f(x)f(x) with its corresponding derivative f(x)f'(x).

Functions:

  • f(x)=2xf(x) = \frac{2}{x}
  • f(x)=ln(x)f(x) = \ln(x)
  • f(x)=ln(x2)f(x) = \ln(x^2)
  • f(x)=xf(x) = x
  • f(x)=1xf(x) = \frac{1}{x}
  • f(x)=exf(x) = e^x

Derivatives:

  1. f(x)=2x2f'(x) = \frac{-2}{x^2}
  2. f(x)=2xf'(x) = \frac{2}{x}
  3. f(x)=1x2f'(x) = \frac{-1}{x^2}
  4. f(x)=1xf'(x) = \frac{1}{x}
  5. f(x)=1f'(x) = 1
  6. f(x)=exf'(x) = e^x

Now, let's find the derivatives for each of the provided functions and match them:

  1. f(x)=2xf(x) = \frac{2}{x}
    Derivative:
    f(x)=ddx(2x)=2x2f'(x) = \frac{d}{dx} \left( \frac{2}{x} \right) = \frac{-2}{x^2}
    This matches derivative f(x)=2x2f'(x) = \frac{-2}{x^2}.

  2. f(x)=ln(x)f(x) = \ln(x)
    Derivative:
    f(x)=ddx(ln(x))=1xf'(x) = \frac{d}{dx} \left( \ln(x) \right) = \frac{1}{x}
    This matches derivative f(x)=1xf'(x) = \frac{1}{x}.

  3. f(x)=ln(x2)f(x) = \ln(x^2)
    Using the logarithmic property ln(x2)=2ln(x)\ln(x^2) = 2 \ln(x), its derivative is:
    f(x)=ddx(2ln(x))=2xf'(x) = \frac{d}{dx} \left( 2 \ln(x) \right) = \frac{2}{x}
    This matches derivative f(x)=2xf'(x) = \frac{2}{x}.

  4. f(x)=xf(x) = x
    Derivative:
    f(x)=ddx(x)=1f'(x) = \frac{d}{dx} (x) = 1
    This matches derivative f(x)=1f'(x) = 1.

  5. f(x)=1xf(x) = \frac{1}{x}
    Derivative:
    f(x)=ddx(1x)=1x2f'(x) = \frac{d}{dx} \left( \frac{1}{x} \right) = \frac{-1}{x^2}
    This matches derivative f(x)=1x2f'(x) = \frac{-1}{x^2}.

  6. f(x)=exf(x) = e^x
    Derivative:
    f(x)=ddx(ex)=exf'(x) = \frac{d}{dx} \left( e^x \right) = e^x
    This matches derivative f(x)=exf'(x) = e^x.

Correct Matches:

  1. f(x)=2xf(x) = \frac{2}{x} matches f(x)=2x2f'(x) = \frac{-2}{x^2}
  2. f(x)=ln(x2)f(x) = \ln(x^2) matches f(x)=2xf'(x) = \frac{2}{x}
  3. f(x)=1xf(x) = \frac{1}{x} matches f(x)=1x2f'(x) = \frac{-1}{x^2}
  4. f(x)=ln(x)f(x) = \ln(x) matches f(x)=1xf'(x) = \frac{1}{x}
  5. f(x)=xf(x) = x matches f(x)=1f'(x) = 1
  6. f(x)=exf(x) = e^x matches f(x)=exf'(x) = e^x

Would you like more details on any specific part of this solution?

Related Questions:

  1. How do you apply the chain rule in differentiation?
  2. What is the derivative of a natural logarithmic function?
  3. How does the power rule apply to f(x)=xnf(x) = x^n?
  4. Can you explain logarithmic differentiation with examples?
  5. What is the significance of the derivative of exponential functions?

Tip:

When differentiating logarithmic functions, use properties like ln(ab)=bln(a)\ln(a^b) = b \ln(a) to simplify before finding the derivative.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Calculus
Derivatives
Logarithmic Differentiation
Exponential Functions

Formulas

Derivative of f(x) = ln(x) is f'(x) = 1/x
Derivative of f(x) = e^x is f'(x) = e^x
Derivative of f(x) = 1/x is f'(x) = -1/x^2
Derivative of f(x) = 2/x is f'(x) = -2/x^2
Derivative of f(x) = x is f'(x) = 1
Logarithmic property: ln(x^2) = 2ln(x)

Theorems

Power Rule
Logarithmic Differentiation
Chain Rule

Suitable Grade Level

Grades 11-12, Early University Level