Math Problem Statement

Find the marginal revenue product if 20 employees produce x unit of a product per day where; 

x = 2n (3n + 1)^2 and the demand function for a product is given by p=535/(x+5)^2

Solution

The marginal revenue product (MRP) is calculated as the additional revenue generated by employing one more unit of input (in this case, labor). In your case, this is the additional revenue produced by the 21st employee, and it involves two components:

  1. Marginal product of labor (MPL): The additional output produced by hiring one more worker.
  2. Marginal revenue (MR): The additional revenue generated from selling the additional output.

Step 1: Marginal Product of Labor (MPL)

The production function is given as:

x=2n(3n+1)2x = 2n (3n + 1)^2

where xx is the number of units produced and nn is the number of workers. To find the marginal product of labor (MPL), we need to find how the output xx changes with respect to the number of workers nn. This means finding the derivative of xx with respect to nn.

dxdn=MPL\frac{dx}{dn} = \text{MPL}

Using the product rule for differentiation:

x=2n(3n+1)2x = 2n(3n+1)^2

Differentiate:

dxdn=2(3n+1)2+2n2(3n+1)3\frac{dx}{dn} = 2(3n+1)^2 + 2n \cdot 2(3n+1) \cdot 3

Simplifying:

dxdn=2(3n+1)2+12n(3n+1)\frac{dx}{dn} = 2(3n+1)^2 + 12n(3n+1)

=2(3n+1)[(3n+1)+6n]=2(3n+1)(9n+1)= 2(3n+1)[(3n+1) + 6n] = 2(3n+1)(9n+1)

So the marginal product of labor is:

dxdn=2(3n+1)(9n+1)\frac{dx}{dn} = 2(3n+1)(9n+1)

Step 2: Marginal Revenue (MR)

The price pp of the product is given by the demand function:

p=535(x+5)2p = \frac{535}{(x+5)^2}

The total revenue RR is:

R=px=535x(x+5)2R = p \cdot x = \frac{535x}{(x+5)^2}

Now, to find the marginal revenue, we take the derivative of revenue RR with respect to xx:

dRdx=MR\frac{dR}{dx} = \text{MR}

Using the quotient rule for differentiation:

dRdx=(x+5)2535535x2(x+5)(x+5)4\frac{dR}{dx} = \frac{(x+5)^2 \cdot 535 - 535x \cdot 2(x+5)}{(x+5)^4}

Simplify:

dRdx=535[(x+5)22x(x+5)](x+5)4\frac{dR}{dx} = \frac{535[(x+5)^2 - 2x(x+5)]}{(x+5)^4}

Further simplification leads to:

dRdx=535[25x2](x+5)4\frac{dR}{dx} = \frac{535[25 - x^2]}{(x+5)^4}

So the marginal revenue is:

MR=535(25x2)(x+5)4\text{MR} = \frac{535(25 - x^2)}{(x+5)^4}

Step 3: Marginal Revenue Product (MRP)

The marginal revenue product is the product of the marginal product of labor (MPL) and the marginal revenue (MR):

MRP=MPLMR\text{MRP} = \text{MPL} \cdot \text{MR}

Substituting the values we derived:

[ \text{MRP} = \left[ 2(3n+1)(9n+1) \right] \cdot \left[ \frac{535(25 - x^2)}{(x+5)^4} \right] ]

This gives the marginal revenue product, though a numerical result can be obtained by substituting specific values for nn (like n=20n = 20) and corresponding xx.

Would you like a detailed numerical solution, or do you have any specific clarifications so far?


Here are 5 related questions to expand this concept:

  1. How does marginal revenue change if demand elasticity changes?
  2. What is the significance of diminishing marginal returns in this context?
  3. How would changes in the demand function impact the marginal revenue product?
  4. Can you interpret what happens when the marginal product of labor becomes negative?
  5. What role does pricing strategy play in determining marginal revenue?

Tip: Understanding the relationship between marginal product and marginal revenue can help optimize labor and production costs effectively.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Calculus
Differentiation
Marginal Analysis
Productivity
Revenue

Formulas

Marginal Product of Labor (MPL) = dx/dn
Marginal Revenue (MR) = dR/dx
Total Revenue (R) = p * x
Marginal Revenue Product (MRP) = MPL * MR

Theorems

Product rule of differentiation
Quotient rule of differentiation

Suitable Grade Level

Grades 11-12 / College-level Calculus