Math Problem Statement

For the equations​ below, q is the total number of units produced per day by m employees of a​ manufacturer, and p is the price per unit at which the q units are sold. Find the​ marginal-revenue product for the given value of m. qequalsStartFraction 200 m minus m squared Over 20 EndFraction ​, pequalsnegative 0.3 q plus 80​; m equals 90

Solution

To find the marginal-revenue product (MRP) for the given value of m=90m = 90, we follow these steps:

1. Define the functions:

  • The production function is given by: q=200mm220q = \frac{200m - m^2}{20}
  • The price function is given by: p=0.3q+80p = -0.3q + 80

The marginal-revenue product (MRP) is the additional revenue generated from hiring one more worker. It can be calculated as: MRP=dRdm\text{MRP} = \frac{dR}{dm} Where RR is the total revenue: R=pqR = p \cdot q

2. Find qq as a function of mm:

The production function is already given as: q(m)=200mm220q(m) = \frac{200m - m^2}{20} We differentiate this to find dqdm\frac{dq}{dm}: dqdm=120(2002m)=2002m20\frac{dq}{dm} = \frac{1}{20} (200 - 2m) = \frac{200 - 2m}{20}

3. Express pp in terms of mm:

Since p=0.3q+80p = -0.3q + 80, substitute the expression for qq into the price function: p(m)=0.3(200mm220)+80p(m) = -0.3 \cdot \left(\frac{200m - m^2}{20}\right) + 80 Simplifying:

= \frac{-60m + 0.3m^2}{20} + 80 = \frac{-3m + 0.015m^2}{1} + 80$$ So: $$p(m) = 80 - 3m + 0.015m^2$$ ### 4. Find the revenue $$R$$: The total revenue is: $$R(m) = p(m) \cdot q(m)$$ Substitute the expressions for $$p(m)$$ and $$q(m)$$: $$R(m) = \left(80 - 3m + 0.015m^2\right) \cdot \left(\frac{200m - m^2}{20}\right)$$ ### 5. Differentiate $$R(m)$$ to find $$\frac{dR}{dm}$$: Now, we differentiate $$R(m)$$ with respect to $$m$$ to find the marginal-revenue product, $$\text{MRP}(m) = \frac{dR}{dm}$$. Let me perform the calculation to find the MRP at $$m = 90$$.The marginal-revenue product (MRP) at $$m = 90$$ is $$-217$$. This negative value indicates that producing additional units by hiring more employees beyond this point would reduce revenue. Would you like more details or have any questions? Here are 5 related questions to explore further: 1. How does marginal-revenue product change as the number of employees increases? 2. What does a negative MRP imply for business decisions? 3. How would the result change if the production function had a different form? 4. How can you determine the optimal number of employees based on MRP? 5. How is MRP related to labor demand in economics? **Tip:** Marginal-revenue product helps businesses decide the optimal level of labor input, balancing production efficiency and costs.

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Math Problem Analysis

Mathematical Concepts

Differentiation
Marginal Revenue Product
Revenue Function

Formulas

q(m) = (200m - m^2) / 20
p(q) = -0.3q + 80
R(m) = p(m) * q(m)
MRP = dR/dm

Theorems

Marginal revenue product (MRP): The derivative of total revenue with respect to labor
Product Rule for differentiation

Suitable Grade Level

College-level (Economics/Calculus)