 If you could multiply, add, subtract, and divide, how could you make 82, with the numbers 1, 1, 2, 4, and 7 without using a number twice

To make 82 using the numbers 1, 1, 2, 4, and 7, without repeating any number, here's one possible approach:

\[
(7 \times 12) - (4 + 2 + 1) = 82
\]

Here's the breakdown:
1. Multiply 7 by 12 (formed by 1 and 2) to get 84.
2. Add 4 + 2 + 1, which equals 7.
3. Subtract 7 from 84 to get 82.

Let me know if you'd like further explanation or more examples! 

### Related Questions:
1. Can we create 82 using different operations, like powers or factorials?
2. How would you form 82 if allowed to repeat numbers once?
3. How can you create other numbers using just basic arithmetic operations and a fixed set of numbers?
4. Is there a general strategy for maximizing results with a fixed set of numbers?
5. What happens if we introduce parentheses for altering order of operations?

**Tip:** Working with multiplication and addition often helps achieve larger results, so focusing on combinations of those can be a good starting point.

If you could multiply, add, subtract, and divide, how could you make 82, with the numbers 1, 1, 2, 4, and 7 without using a number twice?

Discover how to use multiplication, addition, and subtraction to make 82 with the numbers 1, 1, 2, 4, and 7, without repeating any number. This math puzzle focuses on arithmetic operations and logical number combinations. Ideal for students in Grades 6-8.

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