The equation you're providing is:

$3^{\log 9} = 2$

If we attempt to solve this equation for $\log 9$, we first recognize that this is a logarithmic equation with a base $3$.

First, express $\log 9$ in terms of logarithms:

$3^{\log 9} = 2$

This is an incorrect equation based on the standard interpretation of logarithms. Instead, the correct equation should be rechecked or further clarified. Would you like to clarify or review the original problem?

Here are related concepts:

1. How to solve for the logarithm of a number.
2. How to convert logarithmic equations to exponential form.
3. What is the general solution of logarithmic equations?
4. How do logarithmic identities like change of base work?
5. Examples of equations using logarithms.

Tip: Always recheck if the bases in logarithmic or exponential equations match, as it affects the solution.