Math Problem Statement

Consider the following data on shoulder girth and height of a group of physically active adults. The mean shoulder girth is 107.60 cm with a standard deviation of 10.36 cm. The mean height is 171.16 cm with a standard deviation of 9.39 cm. The correlation between height and shoulder girth is 0.69.

A scatterplot has a horizontal axis labeled "Shoulder girth (cm)" with values from 85 to 135 and a vertical axis labeled "Height (cm)" with values from 145 to 200. The scatterplot has many points. A pattern goes up and right from (86, 145) to (134, 199). The points are scattered moderately from the pattern. (a) Write the equation of the regression line for predicting height. (Let y represent height in centimeters and let x represent shoulder girth in centimeters. Round your numerical values to three decimal places.) ŷ =

Incorrect: Your answer is incorrect. (b) Interpret the slope in this context. (Round your answer to three decimal places.) For each centimeter increase in shoulder girth, we would expect height to increase on average by .625

Correct: Your answer is correct. centimeters. Interpret the intercept in this context. (Round your answer to three decimal places.) People who have a shoulder girth of 0 centimeters are expected to be on average

Incorrect: Your answer is incorrect. centimeters tall.

Solution

To find the equation of the regression line for predicting height based on shoulder girth, we need to use the formula for a simple linear regression line:

y^=b0+b1x\hat{y} = b_0 + b_1x

where:

  • y^\hat{y} is the predicted height,
  • b0b_0 is the intercept,
  • b1b_1 is the slope,
  • xx is the shoulder girth.

We need the following values for the calculation:

  • The correlation coefficient r=0.69r = 0.69,
  • The standard deviation of height sy=9.39s_y = 9.39,
  • The standard deviation of shoulder girth sx=10.36s_x = 10.36,
  • The mean height yˉ=171.16\bar{y} = 171.16,
  • The mean shoulder girth xˉ=107.60\bar{x} = 107.60.

Step 1: Calculate the slope (b1b_1)

The formula for the slope is:

b1=r×sysxb_1 = r \times \frac{s_y}{s_x}

Substituting the values:

b1=0.69×9.3910.36=0.625b_1 = 0.69 \times \frac{9.39}{10.36} = 0.625

So, the slope b1b_1 is 0.625.

Step 2: Calculate the intercept (b0b_0)

The formula for the intercept is:

b0=yˉb1×xˉb_0 = \bar{y} - b_1 \times \bar{x}

Substituting the values:

b0=171.160.625×107.60b_0 = 171.16 - 0.625 \times 107.60

b0=171.1667.25=103.91b_0 = 171.16 - 67.25 = 103.91

So, the intercept b0b_0 is 103.91.

Final regression equation:

y^=103.910+0.625x\hat{y} = 103.910 + 0.625x

Part (b): Interpretation of the intercept

The intercept represents the predicted height when the shoulder girth is 0 cm. This is not a realistic value in this context, since no one would have a shoulder girth of 0 cm, so the intercept doesn't have a meaningful interpretation in practical terms. It is simply a necessary part of the regression equation.

Would you like to go deeper into any of these steps or details?


Here are some follow-up questions to extend your understanding:

  1. How does the correlation value affect the slope of the regression line?
  2. What are the assumptions of the linear regression model, and how could they be violated?
  3. Why is the intercept not meaningful in this context, and what would happen if we forced it to be 0?
  4. How would the regression equation change if the correlation were negative?
  5. How could outliers in the data impact the regression line?

Tip: Always examine the residuals of your regression to check for any patterns, which can indicate if the linear model is appropriate.

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Math Problem Analysis

Mathematical Concepts

Linear Regression
Correlation Coefficient
Slope and Intercept
Prediction in Statistics

Formulas

Regression line equation: ŷ = b0 + b1x
Slope: b1 = r * (sy / sx)
Intercept: b0 = ȳ - b1 * x̄

Theorems

Least Squares Method
Linear Relationship between Two Variables

Suitable Grade Level

Undergraduate Statistics or Advanced High School (Grades 11-12)