Math Problem Statement

The table below gives the list price and the number of bids received for five randomly selected items sold through online auctions. Using this data, consider the equation of the regression line, yˆ=b0+b1x , for predicting the number of bids an item will receive based on the list price. Keep in mind, the correlation coefficient may or may not be statistically significant for the data given. Remember, in practice, it would not be appropriate to use the regression line to make a prediction if the correlation coefficient is not statistically significant.

Price in Dollars 23 26 28 34 49 Number of Bids 1 2 5 9 10 Table

Step 1 of 6 : Find the estimated slope. Round your answer to three decimal places.

Solution

To find the estimated slope b1b_1 of the regression line, we will use the formula:

b1=nxyxynx2(x)2b_1 = \frac{n \sum{xy} - \sum{x} \sum{y}}{n \sum{x^2} - (\sum{x})^2}

Where:

  • nn is the number of data points (5 in this case),
  • xx represents the list prices of the items,
  • yy represents the number of bids,
  • xy\sum{xy} is the sum of the products of each pair of xx and yy,
  • x\sum{x} is the sum of the list prices,
  • y\sum{y} is the sum of the number of bids,
  • x2\sum{x^2} is the sum of the squares of the list prices.

Step 1: Calculate necessary sums

  1. List prices (x): 23, 26, 28, 34, 49
  2. Number of bids (y): 1, 2, 5, 9, 10

Let's calculate the sums of the required terms.

  • x=23+26+28+34+49=160\sum{x} = 23 + 26 + 28 + 34 + 49 = 160
  • y=1+2+5+9+10=27\sum{y} = 1 + 2 + 5 + 9 + 10 = 27
  • x2=232+262+282+342+492=529+676+784+1156+2401=5546\sum{x^2} = 23^2 + 26^2 + 28^2 + 34^2 + 49^2 = 529 + 676 + 784 + 1156 + 2401 = 5546
  • xy=(23×1)+(26×2)+(28×5)+(34×9)+(49×10)=23+52+140+306+490=1011\sum{xy} = (23 \times 1) + (26 \times 2) + (28 \times 5) + (34 \times 9) + (49 \times 10) = 23 + 52 + 140 + 306 + 490 = 1011

Now, we can substitute these values into the formula for b1b_1:

b1=5(1011)(160)(27)5(5546)(160)2b_1 = \frac{5(1011) - (160)(27)}{5(5546) - (160)^2} b1=505543202773025600b_1 = \frac{5055 - 4320}{27730 - 25600} b1=7352130b_1 = \frac{735}{2130} b10.345b_1 \approx 0.345

Conclusion:

The estimated slope b1b_1 of the regression line is approximately 0.345 (rounded to three decimal places).

Would you like to proceed with the next steps or have any questions about this part? Here are some related questions:

  1. How do you interpret the meaning of the slope in this context?
  2. How would you calculate the estimated intercept b0b_0 of the regression line?
  3. What is the formula for the regression line once you have the slope and intercept?
  4. How would you use the regression line to predict the number of bids for a given price?
  5. How do you calculate the correlation coefficient from the data?

Tip: Ensure you understand how to interpret both the slope and the intercept in real-world scenarios, as they give insight into the relationship between the variables.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Linear Regression
Statistics
Correlation
Slope of a Line

Formulas

b1 = (nΣxy - ΣxΣy) / (nΣx² - (Σx)²)

Theorems

Least Squares Method
Regression Line Interpretation

Suitable Grade Level

Grades 10-12